A 35.2 HP, 250 V, 100 A, 1800 RPM, series DC motor with no armature reaction is considered inthis problem.This motor has a series-field winding of 15 turns per pole. Its armature resistance in RA=0.05 2, andits series field resistance is Rs 0.05 2.The magnetization curve at 1800 RPM is given by the following table:EA (V)509512515018020021225022924325320050075510001280150020002500 3000 3500 4000(Amp.turns)The motor is operating at rated voltage, armature current of 100 Amperes, and with rotational lossesof 1500 Watt.Find the speed orthe motor.Select one:a. Speed n = 2160 RPMb. NoneO c. Speedn 1500 RPMO d. Speed 1800 RPMConsider a separately-excited DC motor with an armature resistance RA =0.15 2 and terminal voltage VT=Sho 07011This courseConsider a shunt DC motor with an armature resistance RA=0.1252 and terminal voltageVT 380V. The motor rated speed is 1000 RPM and the rated armature current is 100 A.The total field resistance is 260 Ohms.IF (A)EA (V)0.00.10.20.30.40.50.60.70.83085These values were taken at speed n= 1000 RPM60102115124130134What is the starting armature current of this motor?Select one:a. NoneO b. Starting Cuhent = 4030 AmpO c. Starting Current = 2500 AmpO d. Starting Current 3040 AmpA35.2 HP, 250 V. 100 A. 1800 RPM, series DC motor with no armature reaction is considered inthis problem.This motor has a series-field winding of 15 turns per pole. Its armature resistance in RA=0.05 2, and

As per our policy, i am attempting first question. Given data, Ia=100 AIse=100 ARa=0.05 ΩRse=0.05…

A 35.2 HP, 250 V, 100 A, 1800 RPM, series DC motor with no armature reaction is considered in this problem. This motor has a series-field winding of 15 turns per pole. Its armature resistance in RA=0.05 2, and its series field resistance is Rs=0.05 2. The magnetization curve at 1800 RPM is given by the following table: EA (V) 50 95 125 150 180 200 212 229 243 250 253 F 200 500 755 1000 1280 1500 2000 2500 3000 3500 4000 (Amp.turns) The motor is operating at rated voltage, armature current of 100 Amperes, and with rotational losses of 1500 Watt. Find the speed ohthe motor. Select one: a. Speed n = 2160 RPM b. None Oc. Speedn 1500 RPM O d. Speed = 1800 RPM

A 35.2 HP, 250 V, 100 A, 1800 RPM, series DC motor with no armature reaction is considered in this problem. This motor has a series-field winding of 15 turns per pole. Its armature resistance in RA=0.05 2, and its series field resistance is Rs=0.05 2. The magnetization curve at 1800 RPM is given by the following table: EA (V) 50 95 125 150 180 200 212 229 243 250 253 F 200 500 755 1000 1280 1500 2000 2500 3000 3500 4000 (Amp.turns) The motor is operating at rated voltage, armature current of 100 Amperes, and with rotational losses of 1500 Watt. Find the speed ohthe motor. Select one: a. Speed n = 2160 RPM b. None Oc. Speedn 1500 RPM O d. Speed = 1800 RPM

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Motor Load, Torque, and Power Quality Requirement

An electric motor is a gadget that changes electrical energy into mechanical energy over to follow up on a mechanical burden. The weight set on the motor because of this mechanical movement is known as motor load. Appropriately matching the motor burden to the engine is vital to forestall harm to the engine or wasteful and unnecessary expensive activity. Engines perform such undertakings as moving a thing starting with one spot then onto the next, cutting it, changing its shape, etc. The motors might be evaluated as far as a few variables including power yield, voltage, current, and temperature. Harm to an engine might happen when it is worked under over the top engine load contrasted with its appraised limit.

Question

A 35.2 HP, 250 V, 100 A, 1800 RPM, series DC motor with no armature reaction is considered in
this problem.
This motor has a series-field winding of 15 turns per pole. Its armature resistance in RA=0.05 2, and
its series field resistance is Rs 0.05 2.
The magnetization curve at 1800 RPM is given by the following table:
EA (V)
50
95
125
150
180
200
212
250
229
243
253
200
500
755
1000
1280
1500
2000
2500 3000 3500 4000
(Amp.turns)
The motor is operating at rated voltage, armature current of 100 Amperes, and with rotational losses
of 1500 Watt.
Find the speed orthe motor.
Select one:
a. Speed n = 2160 RPM
b. None
O c. Speedn 1500 RPM
O d. Speed 1800 RPM
Consider a separately-excited DC motor with an armature resistance RA =0.15 2 and terminal voltage VT=
Sho

07011
This course
Consider a shunt DC motor with an armature resistance RA=0.1252 and terminal voltage
VT 380V. The motor rated speed is 1000 RPM and the rated armature current is 100 A.
The total field resistance is 260 Ohms.
IF (A)
EA (V)
0.0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
30
85
These values were taken at speed n= 1000 RPM
60
102
115
124
130
134
What is the starting armature current of this motor?
Select one:
a. None
O b. Starting Cuhent = 4030 Amp
O c. Starting Current = 2500 Amp
O d. Starting Current 3040 Amp
A35.2 HP, 250 V. 100 A. 1800 RPM, series DC motor with no armature reaction is considered in
this problem.
This motor has a series-field winding of 15 turns per pole. Its armature resistance in RA=0.05 2, and

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