A 33.5 mL sample of a 0.280 M solution of NaCN is titrated by 0.260 M HCI. K, for CN is 2.0 x 10 %. Calculate the pH of the solution: a. prior to the start of the titration pH b. after the addition of 18.0 mL of 0.260 M HCI pH = c. at the equivalence point pH d. after the addition of 53.0 mL of 0.260 M HCI pH

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A 33.5 mL sample of a 0.280 M solution of NaCN is titrated by 0.260 M HCI. K,
for CN is 2.0 x 10 *. Calculate the pH of the solution:
a. prior to the start of the titration
pH =
b. after the addition of 18.0 mL of 0.260 M HCI
pH =
c. at the equivalence point
pH =
d. after the addition of 53.0 mL of 0.260 M HCI
pH
Transcribed Image Text:A 33.5 mL sample of a 0.280 M solution of NaCN is titrated by 0.260 M HCI. K, for CN is 2.0 x 10 *. Calculate the pH of the solution: a. prior to the start of the titration pH = b. after the addition of 18.0 mL of 0.260 M HCI pH = c. at the equivalence point pH = d. after the addition of 53.0 mL of 0.260 M HCI pH
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