A 320 Н M In isosceles AHAM, m&A = 32°,. What is m ZH? 32° 58° O 74° 148°

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
ChapterCSR: Contents Of Student Resources
Section: Chapter Questions
Problem 1.39EP
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### Problem Statement: Geometry - Isosceles Triangle

#### Diagram:
The diagram shows an isosceles triangle \( \triangle HAM \) with the following characteristics:
- Vertex \( A \) is the apex of the isosceles triangle.
- \( \angle A \) measures \( 32^\circ \).
- The sides \( HA \) and \( MA \) are marked as equal (congruent).

The vertices are labeled as follows:
- \( H \) and \( M \) are the base vertices.
- \( A \) is the vertex opposite the base \( HM \).

#### Question:
In isosceles \( \triangle HAM \), \( m \angle A = 32^\circ \). What is \( m \angle H \)?

#### Choices:
- \( 32^\circ \)
- \( 58^\circ \)
- \( 74^\circ \)
- \( 148^\circ \)

#### Solution Explanation:
To solve for \( m \angle H \), we use the properties of isosceles triangles and the fact that the sum of internal angles of a triangle is \( 180^\circ \).

Given that \( \triangle HAM \) is isosceles with \( HA = MA \), the base angles \( \angle H \) and \( \angle M \) are equal. Let \( m \angle H = m \angle M = x \).

Thus, we have:
\[ m \angle A + m \angle H + m \angle M = 180^\circ \]

Substitute the known values:
\[ 32^\circ + x + x = 180^\circ \]
\[ 32^\circ + 2x = 180^\circ \]
\[ 2x = 180^\circ - 32^\circ \]
\[ 2x = 148^\circ \]
\[ x = 74^\circ \]

Therefore, \( m \angle H = 74^\circ \).

#### Correct Answer:
- \( 74^\circ \)

---

This question helps students practice understanding properties of isosceles triangles, specifically the internal angle relationships and sum of angles in a triangle.
Transcribed Image Text:### Problem Statement: Geometry - Isosceles Triangle #### Diagram: The diagram shows an isosceles triangle \( \triangle HAM \) with the following characteristics: - Vertex \( A \) is the apex of the isosceles triangle. - \( \angle A \) measures \( 32^\circ \). - The sides \( HA \) and \( MA \) are marked as equal (congruent). The vertices are labeled as follows: - \( H \) and \( M \) are the base vertices. - \( A \) is the vertex opposite the base \( HM \). #### Question: In isosceles \( \triangle HAM \), \( m \angle A = 32^\circ \). What is \( m \angle H \)? #### Choices: - \( 32^\circ \) - \( 58^\circ \) - \( 74^\circ \) - \( 148^\circ \) #### Solution Explanation: To solve for \( m \angle H \), we use the properties of isosceles triangles and the fact that the sum of internal angles of a triangle is \( 180^\circ \). Given that \( \triangle HAM \) is isosceles with \( HA = MA \), the base angles \( \angle H \) and \( \angle M \) are equal. Let \( m \angle H = m \angle M = x \). Thus, we have: \[ m \angle A + m \angle H + m \angle M = 180^\circ \] Substitute the known values: \[ 32^\circ + x + x = 180^\circ \] \[ 32^\circ + 2x = 180^\circ \] \[ 2x = 180^\circ - 32^\circ \] \[ 2x = 148^\circ \] \[ x = 74^\circ \] Therefore, \( m \angle H = 74^\circ \). #### Correct Answer: - \( 74^\circ \) --- This question helps students practice understanding properties of isosceles triangles, specifically the internal angle relationships and sum of angles in a triangle.
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