Find a in degrees. 58 3 7 [?]°

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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The image shows a right-angled triangle with sides labeled 3, 7, and \(\sqrt{58}\). The angle opposite the side of length 7 is denoted as \(\alpha\). The task is to find the measure of angle \(\alpha\) in degrees, rounding to the nearest tenth.

### Triangle Description:

- The side of length 3 is adjacent to \(\alpha\).
- The side of length 7 is opposite \(\alpha\).
- The hypotenuse is \(\sqrt{58}\).

### Instructions:

To find angle \(\alpha\), use the trigonometric function tangent, which is the ratio of the opposite side to the adjacent side:
\[ 
\tan(\alpha) = \frac{7}{3} 
\]

To find \(\alpha\), you calculate:
\[ 
\alpha = \tan^{-1}\left(\frac{7}{3}\right) 
\]

Finally, round the answer to the nearest tenth of a degree.
Transcribed Image Text:The image shows a right-angled triangle with sides labeled 3, 7, and \(\sqrt{58}\). The angle opposite the side of length 7 is denoted as \(\alpha\). The task is to find the measure of angle \(\alpha\) in degrees, rounding to the nearest tenth. ### Triangle Description: - The side of length 3 is adjacent to \(\alpha\). - The side of length 7 is opposite \(\alpha\). - The hypotenuse is \(\sqrt{58}\). ### Instructions: To find angle \(\alpha\), use the trigonometric function tangent, which is the ratio of the opposite side to the adjacent side: \[ \tan(\alpha) = \frac{7}{3} \] To find \(\alpha\), you calculate: \[ \alpha = \tan^{-1}\left(\frac{7}{3}\right) \] Finally, round the answer to the nearest tenth of a degree.
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