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A 32-2 resistor is put in series with a 30-2 resistor. Calculate the single resistance equivalent to these two.

A 32-2 resistor is put in series with a 30-2 resistor. Calculate the single resistance equivalent to these two.

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**Problem Statement:** A 32-Ω resistor is put in series with a 30-Ω resistor. Calculate the single resistance equivalent to these two. --- **Explanation:** When resistors are placed in series, their resistances add up. The formula for the total resistance \( R_{\text{total}} \) in a series circuit is: \[ R_{\text{total}} = R_1 + R_2 \] Substituting the given values: \[ R_{\text{total}} = 32 \, \Omega + 30 \, \Omega = 62 \, \Omega \] The equivalent resistance of the two resistors in series is 62 Ω.
Transcribed Image Text:**Problem Statement:** A 32-Ω resistor is put in series with a 30-Ω resistor. Calculate the single resistance equivalent to these two. --- **Explanation:** When resistors are placed in series, their resistances add up. The formula for the total resistance \( R_{\text{total}} \) in a series circuit is: \[ R_{\text{total}} = R_1 + R_2 \] Substituting the given values: \[ R_{\text{total}} = 32 \, \Omega + 30 \, \Omega = 62 \, \Omega \] The equivalent resistance of the two resistors in series is 62 Ω.
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Step 1: Concept

Concept of resistors in series

R equals R subscript 1 plus R subscript 2

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