step by step please **Question:**A 300 mg sample of caffeine was dissolved in 10.0 g of camphor (\(K_f = 39.7 \degree \text{C/m}\)), decreasing the freezing point of camphor by \( 3.07 \degree \text{C} \). What is the molar mass of caffeine?1.00 kg = 1000 g- a. 47.0 g/mol- b. 388 g/mol- c. 97.0 g/mol- d. 194 g/mol- e. 94.0 g/mol**Explanation:**To determine the molar mass of caffeine, we utilize the formula for freezing point depression: \[ \Delta T_f = K_f \cdot m \]where \( \Delta T_f \) is the freezing point depression, \( K_f \) is the cryoscopic constant, and \( m \) is the molality of the solution.Given:- \( \Delta T_f = 3.07 \degree \text{C} \)- \( K_f = 39.7 \degree \text{C/m} \)- Mass of camphor (solvent) = 10.0 g = 0.010 kg- Mass of caffeine (solute) = 300 mg = 0.300 gFirst, we calculate the molality (\( m \)) of the solution:\[ m = \frac{\Delta T_f}{K_f} = \frac{3.07 \degree \text{C}}{39.7 \degree \text{C/m}} = 0.0773 \text{ m} \]Molality (\( m \)) is defined as the number of moles of solute per kilogram of solvent, so:\[ m = \frac{\text{moles of caffeine}}{\text{kg of camphor}} \]We rearrange to find the moles of caffeine:\[ \text{moles of caffeine} = m \times \text{kg of camphor} = 0.0773 \text{ m} \times 0.010 \text{ kg} = 0.000773 \text{ moles} \]Finally, we find the molar mass of caffeine (\( M \)) using:\[ M = \frac{\text{mass of caffeine

The expression for depression in freezing point is used to determined the molar mass of solute as…

A 300 mg sample of caffeine was dissolved in 10.0 g of camphor (Ke=39.7°C/m), decreasing the freezing point of camphor by 3.07°C. What is the molar mass of caffeine? 1.00 kg = 1000g 47.0 g/mol O a. 388 g/mol Ob. 97.0 g/mol Oc. 194 g/mol d. 94.0 g/mol Oe. Question 2

A 300 mg sample of caffeine was dissolved in 10.0 g of camphor (Ke=39.7°C/m), decreasing the freezing point of camphor by 3.07°C. What is the molar mass of caffeine? 1.00 kg = 1000g 47.0 g/mol O a. 388 g/mol Ob. 97.0 g/mol Oc. 194 g/mol d. 94.0 g/mol Oe. Question 2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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