A 300-lb block rests on a plane inclined at 36.87° from the horizontal. A 100 lb force pushes this block up the plane. The coefficient of friction between the block and the plane shown is 0.35. If the block is in equilibrium, determine the maximum friction force that can be developed. A 280 lb 80 lb C 63 Ib D) 84 Ib

A 300-lb block rests on a plane inclined at 36.87° from the horizontal. A 100 lb force pushes this block up the plane. The coefficient of friction between the block and the plane shown is 0.35. If the block is in equilibrium, determine the maximum friction force that can be developed. A 280 lb 80 lb C 63 Ib D) 84 Ib

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The tongs are used to lift the 150-kg crate, whose center of mass is at G. Determine which Free Body Diagram can be used to find the least coefficient of static friction at the pivot blocks so that the crate can be lifted. 500 mm 500 mm 275 mm LOS E 300 A H B
--Determine the maximum force P that can be applied without causing movement of the 90-kg crate that has a center of gravity at G. The coefficient of static friction at the floor is p0.5, as shown in the Figure 10. (20 Marks) Fig. (10) 0.5 m 0.5 m 6.7 m
A cast-iron cannonball is found by a diver on the bottom of a harbor (SG of harbor water = 1.02) . The cannonball has a volume of 0.1 ft3 . The cast-iron has a specific gravity of 7.40. What force (F) is necessary to lift the cannonball off the bottom (find F in lb)? (use specific weight of water = 62.4 lb/ft3 )
An A913 Gr. 60 W14x109 is used as a 15-m high column. The column is fixed at both ends and is laterally supported (hinged) at every one-third of its height about the weak axis. 1. Calculate the governing slenderness ratio of the column.2. Calculate the Euler Buckling stress, Fe in MPa.3. Determine the ultimate design strength, in kN
Determine the (a) product moment of inertia at steel cross-sectional area with respect to centroidal axes and then (b) calculate the minor and major principal values of moment of inertia with respect to centroidal axes. (Imin Imax). 250 mm mm TUUR OS 350 mm 50 mm 150 mm
A force P is being applied laterally to the crate which has a center of gravity at G. The coefficient of static friction at the floor is us = 0.4 How much force P should be applied to impend tipping of the crate? Select the correct response 138.89 lb 83.33 lb 100.00 lb 71.43 lb W-250 lb 2.3 3.50
Three identical circular A36 steel columns, A, B, and C, are carrying a 750kN block. The diameter of each column is 30mm. Calculate the normal stress on each column when column B is heated from 20oC to 25oC. Consider: EA36 =200GPa  A36 =0.000012 oC-1 1) What is the effect of column length on the result? 2) Is this structure statically determinate or indeterminate? Why?
The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 400 N is applied to it, determine the change in its length and the change in its diameter. E = 3.20 GPa, v = 0.4. %3D 400 N 400 N 200 mm
As a construction engineer, you are asked to evaluate the maximum allowable vertical shear Vmax that may act on the hollow stainless-steel beam having a rectangular cross section as shown in Figure Q4. Discuss the effect of geometry on the shear stress developed in the beam | 20 mm y 350 mm V 10 mm- -10 mm 1 30 mm E 200 mm
25.3 mm 45mm E x 107 mm The block shown is made of a magnesium alloy for which E=45 GPa and v=0.35. Knowing that ox=-183 MPa, determine (a) the magnitude of oy for which the change in the height of the block will be zero, (b) the corresponding change in the area of the face ABCD, (c) the corresponding change in the volume of the block. D dy THA C B Ox
Determine the resultant force of the water acting on the circular glass plate that Is to the side panel of the tank. Also, determine the location of the center of pressure along this inclined side, measured from the top. Question 2: FYw.h.A ate Fv= Yw.V 3 m radie 9810 Ixr x gate 9810 1 m 2 m Ma:0 Nar3- Fn 号×3-fvx3- -0 Ma=0-) NBx3- F t /2Fy-0 120° 3 m 1,- I,