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A 30-kg iron block initially at 280°C is quenched in an insulated tank that contains 100 kg of water at 18°C. Assuming the water that vaporizes during the process condenses back in the tank, determine the total entropy change during this process. The specific heat of water at 25°C is cp=4.18 kJ/kg-K. The specific heat of iron at room temperature is cp = 0.45 kJ/kg-K. The total entropy change during this process is KJ/K.

A 30-kg iron block initially at 280°C is quenched in an insulated tank that contains 100 kg of water at 18°C. Assuming the water that vaporizes during the process condenses back in the tank, determine the total entropy change during this process. The specific heat of water at 25°C is cp=4.18 kJ/kg-K. The specific heat of iron at room temperature is cp = 0.45 kJ/kg-K. The total entropy change during this process is KJ/K.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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### Problem Statement A 30-kg iron block initially at 280°C is quenched in an insulated tank that contains 100 kg of water at 18°C. Assuming the water that vaporizes during the process condenses back in the tank, determine the total entropy change during this process. - The specific heat of water at 25°C is \( c_p = 4.18 \, \text{kJ/kg} \cdot \text{K} \). - The specific heat of iron at room temperature is \( c_p = 0.45 \, \text{kJ/kg} \cdot \text{K} \). The total entropy change during this process is \(\_\_\_\_\_\_\_\_\_\_\_\_\) kJ/K.
Transcribed Image Text:### Problem Statement A 30-kg iron block initially at 280°C is quenched in an insulated tank that contains 100 kg of water at 18°C. Assuming the water that vaporizes during the process condenses back in the tank, determine the total entropy change during this process. - The specific heat of water at 25°C is \( c_p = 4.18 \, \text{kJ/kg} \cdot \text{K} \). - The specific heat of iron at room temperature is \( c_p = 0.45 \, \text{kJ/kg} \cdot \text{K} \). The total entropy change during this process is \(\_\_\_\_\_\_\_\_\_\_\_\_\) kJ/K.
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