50 grams of water at 20ºC is converted into steam at 250ºC at constant atmospheric pressure. Assuming the heat capacity per gram of liquid water to remain constant at 4.2 J/g K and the heat of vaporization at 100ºC to be 226 J/g, and using Cp/R=a+bT+cT2, calculate the entropy change of the system.

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A: T1=300 Kno. of mole, n=3V1=0.06 m3V2=0.01 m3W=850 J

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Q: Determine the entropy for these states. R-134a, T = 25°C, v = 0.01 m3/kg

A: Given Data: The temperature of R-134a is, T=25°C. The specific volume of R-134a is, v=0.01 m3/kg.

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A: Data given-  Tw  = 95°C = 368 K  mw = 45 kg  Vair = 90 m3  Tair = 12°C = 285 K  Cw = 4.18 kJ/kg  CP…

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Q: pl liquid water 18 cal/mol-K %3D steam (cal/mol-K) = 7.2 + 2.4 x 10-3T

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Q: What is entropy and its application?

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A: In This Problem Concept And Formula Of Thermodynamics Are Used.

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Q: entropy (in kJ/kgK)

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A: the graphs are in last two pages i solved whole question

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Entropy

In physics, entropy means the amount of disorder or the degree of randomness associated with a thermodynamic system. The system is not self-organized when the entropy of the system is high. For instance, when a system is at an elevated temperature, its molecules are in random motion, vibrating and colliding with each other. During this scenario, the probability of finding a molecule at a particular place twice, is low. Under this circumstance, the system can be said to be in a high entropy.