A 3.00 kg box that is several hundred meters above theearth’s surface is suspended from the end of a short vertical rope of negligiblemass. A time-dependent upward force is applied to the upper endof the rope and results in a tension in the rope of T1t2 = (36.0 N/s)t.The box is at rest at t = 0. The only forces on the box are the tension inthe rope and gravity. What is the maximum distance that the box descends below its initial position?

A 3.00 kg box that is several hundred meters above theearth’s surface is suspended from the end of a short vertical rope of negligiblemass. A time-dependent upward force is applied to the upper endof the rope and results in a tension in the rope of T1t2 = (36.0 N/s)t.The box is at rest at t = 0. The only forces on the box are the tension inthe rope and gravity. What is the maximum distance that the box descends below its initial position?

Similar questions

A 250 g container hangs at rest from two strings. The rope under tension Ty is directed at an angle g = 32° from the horizontal direction as shown. What are the tensions Ty and T2 (in N) in the two strings?
Asap plzzz
A 24 kg box is being pulled by a horizontal rope along a floor at aconstant speed (v = 1.0m/s). There is friction between the floor and the box with k = 0.40.a. The formula for tension in the rope is given by:a) T = μk gcosθb) T = Fnsinθc) T = μk mgd) none of these b. What is the magnitude of the tension?
Question 13. A rescue helicopter is lifting a man (weight = 877.22 N) from a capsized boat by means of a cable and harness. (a) What is the tension in the cable when the man is given an initial upward acceleration of 1.36 m/s2? (b) What is the tension during the remainder of the rescue when he is pulled upward at a constant velocity? Ans: 999 N; 877 N moito lir man ties one end of a nylon rope around the free
A traffic light weighing 122 N hangs from a cable tied to two other cablesfastened to a support. The upper cables make angles of 37.0◦ and 53.0◦with the horizontal. These upper cables are not as strong as the verticalcable, and will break if the tension in them exceeds 100 N. Will the trafficlight remain hanging in this situation, or will one of the cables break?
A 11 kg block rests on a 26 degree inclined frictionless surface and is attached by a light string to a 30 kg hanging mass where the string passes over a massless frictionless pulley. If g = 9.8 m/s2, what is the tension in the connecting string?
A block of mass m is pulled at constant velocity along a rough horizontal floor by an applied force P as shown. The magnitude of the frictional force is: ΑΝ f< 7777 OP cos 0 O mg cos 0 OP sin 0 O none of the given choices Omg VFg 7 P 0 TTT F: force of gravity f: frictional force Ñ: normal force
A box of mass 100.0kg rests on level ground and there is no friction between the box and theground. Resting on top of that mass is a 40.0kg mass with friction coecient that's unknown. A ropeis tied to the 100.0 kg mass and draped over a pulley from which a third mass hangs. How much massmust the hanging mass have in order for the acceleration of all masses to be 5ms2 ? What is the minimum possible friction coecient of the 40.0kg mass in the prior problem?
A man inside the elevator stands in a weighing scale, mass = 100 kg. What will be its apparent weight if the elevator is accelerating upward with a magnitude of 8 m/s2.
An Atwood Machine is set up as shown. Mass m1 = 2.00 kg and m2 = 3.00 kg. Assume the connecting string has 0 mass and that there is no friction. The net force on m2 (in Newtons) is The acceleration of m2 (in m/s2) is
Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F. (Figure 1)The magnitude of the tension in the string between blocks B and C is T = 3.00 N . Assume that each block has mass m = 0.400 kg . What is the tension T in the string between block A and block B?
Consider the physical situation shown below. A 21.9-Newton force is applied at a 25-degree angle to the horizontal to accelerate a 5.2-kg box across a rough surface (coefficient of friction = 0.32). Use g = 9.8 m/s/s to fill in all the blanks and determine the acceleration of the box. Ffrict m b C Od = a = Fnorm = Fgrav Fapp = m/s² The Normal force = 51 N The friction force = 16 N The Normal force = 51 N The friction force = 21.9 N The Normal force = 51 N The friction force = 13 N The Normal force = 42N The friction force = 13 N N N