A 3.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0380 m. The spring has force constant 900 N/m. The coefficient of kinetic friction between the floor and the block is 0.400. The block and spring are released from rest and the block slides along the floor.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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---

### Part A

**Problem Statement:**
What is the speed of the block when it has moved a distance of 0.0150 m from its initial position? (At this point, the spring is compressed 0.0230 m). Express your answer with the appropriate units.

**Answer Submission:**
The following input interface is presented to submit the speed \( v \):
```
v =  0.63  m 
                      — 
                      s²        
```

- The value entered: `0.63`
- Units: `m/s²`

**Additional Information:**
- There is a "Submit" button to enter the response.
- Below the submission area, there are two links: "Previous Answers" and "Request Answer."
- An error message displays:
```
✗ Incorrect; Try Again; 4 attempts remaining
```

**Feedback Section:**
A section for feedback is located below the submission area. 

---

This structure helps students to clearly see the problem statement, the input format for answers, and the feedback on their submission attempts.
Transcribed Image Text:--- ### Part A **Problem Statement:** What is the speed of the block when it has moved a distance of 0.0150 m from its initial position? (At this point, the spring is compressed 0.0230 m). Express your answer with the appropriate units. **Answer Submission:** The following input interface is presented to submit the speed \( v \): ``` v =  0.63  m — s² ``` - The value entered: `0.63` - Units: `m/s²` **Additional Information:** - There is a "Submit" button to enter the response. - Below the submission area, there are two links: "Previous Answers" and "Request Answer." - An error message displays: ``` ✗ Incorrect; Try Again; 4 attempts remaining ``` **Feedback Section:** A section for feedback is located below the submission area. --- This structure helps students to clearly see the problem statement, the input format for answers, and the feedback on their submission attempts.
**Exercise 7.24 - Enhanced - with Feedback**

A 3.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0380 m. The spring has a force constant of 900 N/m. The coefficient of kinetic friction between the floor and the block is 0.400. The block and spring are released from rest and the block slides along the floor.

In this exercise, students should analyze the dynamics of the block by considering the initial potential energy stored in the compressed spring, the work done against kinetic friction as the block slides, and how these factors affect the motion of the block. Detailed calculations and step-by-step solutions can be explored to provide a comprehensive understanding of energy conservation and frictional forces in a physical system.

Diagrams and graphs corresponding to this exercise might typically include:

1. **Diagram of the System:**
   - A horizontal line representing the floor.
   - A block labeled with its mass (3.00 kg) on the floor.
   - A spring attached to the block, initially compressed by 0.0380 m.
   - An arrow indicating the direction of the block's motion upon release.
   
2. **Potential Energy vs. Displacement Graph:**
   - A graph plotting potential energy (U = 1/2 kx²) on the y-axis and displacement (x) on the x-axis.
   - Initial and final positions of the block marked clearly.

3. **Frictional Force Representation:**
   - A free-body diagram showing the forces acting on the block, including the spring force and the kinetic friction force.
   - Coefficient of kinetic friction (0.400) used to illustrate frictional force calculation (F_friction = μ * N, where N is the normal force).

These visual aids can help to better illustrate the principles of mechanics involved in the problem, aiding students in grasping the concepts more effectively.
Transcribed Image Text:**Exercise 7.24 - Enhanced - with Feedback** A 3.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0380 m. The spring has a force constant of 900 N/m. The coefficient of kinetic friction between the floor and the block is 0.400. The block and spring are released from rest and the block slides along the floor. In this exercise, students should analyze the dynamics of the block by considering the initial potential energy stored in the compressed spring, the work done against kinetic friction as the block slides, and how these factors affect the motion of the block. Detailed calculations and step-by-step solutions can be explored to provide a comprehensive understanding of energy conservation and frictional forces in a physical system. Diagrams and graphs corresponding to this exercise might typically include: 1. **Diagram of the System:** - A horizontal line representing the floor. - A block labeled with its mass (3.00 kg) on the floor. - A spring attached to the block, initially compressed by 0.0380 m. - An arrow indicating the direction of the block's motion upon release. 2. **Potential Energy vs. Displacement Graph:** - A graph plotting potential energy (U = 1/2 kx²) on the y-axis and displacement (x) on the x-axis. - Initial and final positions of the block marked clearly. 3. **Frictional Force Representation:** - A free-body diagram showing the forces acting on the block, including the spring force and the kinetic friction force. - Coefficient of kinetic friction (0.400) used to illustrate frictional force calculation (F_friction = μ * N, where N is the normal force). These visual aids can help to better illustrate the principles of mechanics involved in the problem, aiding students in grasping the concepts more effectively.
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