## Problem StatementA constant applied force \( F_p \) of 13.0 N pushes a box with a mass \( m = 6.00 \, \text{kg} \) a distance \( x = 15.0 \, \text{m} \) across a level floor. The coefficient of kinetic friction between the box and the floor is 0.130.**Diagram Description**:- The illustration shows a box labeled with mass \( m \) being pushed by the applied force \( F_p \) to the right over a horizontal surface. The box moves a distance \( x \) of 15.0 meters.**Questions**:1. Assuming that the box starts from rest, what is the final velocity \( v_f \) of the box at the 15.0 m point? \[ v_f = \boxed{\phantom{0}} \, \text{m/s} \]2. If there were no friction between the box and the floor, what applied force \( F_{\text{new}} \) would give the box the same final velocity? \[ F_{\text{new}} = \boxed{\phantom{0}} \, \text{N} \]

The work-energy theorem is used to calculate the final velocity of the box.…

A constant applied force F, of 13.0 N pushes a box with a mass m = 6.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.130. F, m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf = m/s If there were no friction between the box and the floor, what applied force Fnew Would give the box the same final velocity? Fnew = N

A constant applied force F, of 13.0 N pushes a box with a mass m = 6.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.130. F, m Assuming that the box starts from rest, what is the final velocity vf of the box at the 15.0 m point? Uf = m/s If there were no friction between the box and the floor, what applied force Fnew Would give the box the same final velocity? Fnew = N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Static and Kinetic Friction

Kinetic friction comes into existence when there are moving surfaces means in other words we can say that the force which comes into existing between moving surfaces is known as kinetic friction.

Question

## Problem Statement

A constant applied force \( F_p \) of 13.0 N pushes a box with a mass \( m = 6.00 \, \text{kg} \) a distance \( x = 15.0 \, \text{m} \) across a level floor. The coefficient of kinetic friction between the box and the floor is 0.130.

**Diagram Description**:
- The illustration shows a box labeled with mass \( m \) being pushed by the applied force \( F_p \) to the right over a horizontal surface. The box moves a distance \( x \) of 15.0 meters.

**Questions**:

1. Assuming that the box starts from rest, what is the final velocity \( v_f \) of the box at the 15.0 m point?
\[
v_f = \boxed{\phantom{0}} \, \text{m/s}
\]

2. If there were no friction between the box and the floor, what applied force \( F_{\text{new}} \) would give the box the same final velocity?
\[
F_{\text{new}} = \boxed{\phantom{0}} \, \text{N}
\]

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