A 3.0-cm-diameter, 18-turn coil of wire, located at z = 0 in the xy-plane, carries a current of 2.5 A. A 2.0-mm-diameter conducting loop with 2.0 x 10-4 resistance is also in the xy-plane at the center of the coil. At t = 0 s, the loop begins to move along the z-axis with a constant speed of 75 m/s. Part A What is the induced current in the conducting loop at t = 200 μs? The diameter of the conducting loop is much smaller than that of the coil, so you can assume that the magnetic field through the loop is everywhere the on-axis field of the coil. Express your answer with the appropriate units. I = μÀ Value Units ?

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### Induced Current in a Conducting Loop

#### Problem Setup

- **Coil Specifications:**
  - Diameter: 3.0 cm
  - Number of Turns: 18
  - Location: \( z = 0 \) in the \( xy \)-plane
  - Current: 2.5 A

- **Conducting Loop Specifications:**
  - Diameter: 2.0 mm
  - Resistance: \( 2.0 \times 10^{-4} \, \Omega \)
  - Initial Position: \( xy \)-plane at the center of the coil
  - Initial Time: \( t = 0 \, \text{s} \)

- **Motion:**
  - The loop begins to move along the \( z \)-axis at a constant speed of 75 m/s.

#### Objective

Calculate the induced current in the conducting loop at \( t = 200 \, \mu\text{s} \).

#### Instructions

- **Assumption:** 
  The diameter of the conducting loop is much smaller than that of the coil. Assume the magnetic field through the loop is the on-axis field of the coil.

- **Solution Approach:** 
  Express the induced current \( I \) with appropriate units.

#### Calculation

The students are expected to calculate the induced current using Faraday's Law of Induction and the properties provided. The small loop's motion and the coil's field must be considered in their calculations. Use the text box provided to input the current \( I \) in the specified units.
Transcribed Image Text:### Induced Current in a Conducting Loop #### Problem Setup - **Coil Specifications:** - Diameter: 3.0 cm - Number of Turns: 18 - Location: \( z = 0 \) in the \( xy \)-plane - Current: 2.5 A - **Conducting Loop Specifications:** - Diameter: 2.0 mm - Resistance: \( 2.0 \times 10^{-4} \, \Omega \) - Initial Position: \( xy \)-plane at the center of the coil - Initial Time: \( t = 0 \, \text{s} \) - **Motion:** - The loop begins to move along the \( z \)-axis at a constant speed of 75 m/s. #### Objective Calculate the induced current in the conducting loop at \( t = 200 \, \mu\text{s} \). #### Instructions - **Assumption:** The diameter of the conducting loop is much smaller than that of the coil. Assume the magnetic field through the loop is the on-axis field of the coil. - **Solution Approach:** Express the induced current \( I \) with appropriate units. #### Calculation The students are expected to calculate the induced current using Faraday's Law of Induction and the properties provided. The small loop's motion and the coil's field must be considered in their calculations. Use the text box provided to input the current \( I \) in the specified units.
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