A 3-processor systems implements cache coherence with a snoopy MESI protocol. For each access in the sequence below (to the same BLOCK address), list the coherence states (M/E/S/I) for each processor's cache after the access. Assume all the cache states begin in the Invalid (1) state. Event P1 state P2 state P3 state P1 reads P2 writes P2 reads P3 writes

A 3-processor systems implements cache coherence with a snoopy MESI protocol. For each access in the sequence below (to the same BLOCK address), list the coherence states (M/E/S/I) for each processor's cache after the access. Assume all the cache states begin in the Invalid (1) state. Event P1 state P2 state P3 state P1 reads P2 writes P2 reads P3 writes

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Consider a direct-mapped cache memory with 12-bit addresses. The cache is byte-addressable. We have B = 16 bytes per block and S = 8 sets. For the address shown below. Indicate which bits correspond to the cache set index, tag bits, and block offset. Bit 11 Bit 10 Bit 9 Bit 8 Bit 7 Bit 6 Bit 5 Bit 4 Bit 3 Bit 2 Bit 1 Bit 0
Question 4
Explain the concept of cache coherence protocols like MOESI (Modified, Owned, Exclusive, Shared, Invalid) and their use in multiprocessor systems.
Suppose we have a byte-addressable computer with a cache that holds 16 blocks of 4 bytes address has 8 bits, to which cache set would the hexadecimal address OxBE map if the computer mapping? each. Assuming that each memory uses 2-way set associative
Cache system B represents a 2-way set-associative mapping cache system in table 2 The system is byte-addressable and the block size is one word (4 bytes). The tag and set numbers are represented with binary numbers. The contents of words in a block are represented with hexadecimal. Tag 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 10 1000 0100 1001 0000 11 1100 0100 1001 0000 Table 2 1. What is the size of the main memory for the Cache system B? Answer= 2. What is the size of the cache memory of Cache system B? Answer = Answer= Answer = 16 Answer = Set Number 16 1011 0110 1101 1011 0110 1101 miss(es) 1011 0110 1110 1011 0110 1110 1011 0110 1111 1011 0110 1111 1011 0111 0000 3. If we request to read memory address F1 24 2D B7, what data do we get? 1011 0111 0000 1011 0111 0001 1011 0111 0001 4. If we…
A 2-way set associative cache consists of four sets. Main memory contains 2K blocks of eight words each. Show the main memory address format that allows us to map addresses from main memory to cache. Be sure to include the fields as well as their sizes. Compute the hit ratio for a program that loops 6 times from locations 8 to 51 in main memory. You may leave the hit ratio in terms of a fraction. Please show details how you obtain the result.
Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a cache of 128 blocks, where each block contains 64 bytes.Q.) To which cache block will the memory address 0x01D872 map?
Below is a series of byte addresses in a system with 32 bit words. Assuming a direct-mapped cache with 4-word blocks and a total size of 32 words that is initially empty, (a) label each reference in the list as a hit or a miss and (b) show the entire history of the cache, including tag and data. Byte Address Byte Address (Hexadecimal) (Binary) Hit/Miss 76 0000 0000 0111 0110 1E3 0000 0001 1110 0011 815 0000 1000 0001 0101 141 0000 0001 0100 0001 170 0000 0001 0111 0000 5E1 0000 0101 1110 0001 320 0000 0011 0010 1100 B10 0000 1011 0001 0000 175 0000 0001 0111 0101 583 0000 0101 1000 0011 1FF 0000 0001 1111 1111 7A 0000 0000 0111 1010 2B2 0000 0010 1011 0010 5E4 0000 0101 1110 0100 816 0000 1000 0001 0110 438 0000 0100 0011 1000
3. The table below represents five lines from a cache that uses fully associative mapping with a block size of 8. Identify the address of the shaded data, 0xE6, first in binary and then in hexadecimal. The tag numbers and word id bits are in binary, but the content of the cache (the data) is in hexadecimal. Word id bits Tag 000 001 010 011 100 101 110 111 ------------------------------------------ 1011010 10 65 BA 0F C4 19 6E C3 1100101 21 76 CB 80 D5 2A 7F B5 0011011 32 87 DC 91 E6 3B F0 A6 1100000 43 98 ED A2 F7 4C E1 97 1111100 54 9A FE B3 08 5D D2 88
Explain the reasons why it is so difficult to devise a suitable cache replacement technique that works for all address sequences.
Given an 8-word, 4-way set associative cache, and the sequence of address accesses below, enter the number of misses. 22 24 22 13 13 22
Consider a 32-bit physical memory space and a 32 KiB 2-way associative cache with LRU replacement. You are told the cache uses 5 bits for the offset field. Write in the number of bits in the tag and index fields. Tag length in bits = Index length in bits =