RAtG•GD.C.mgVoRoat00%3DB3. Which of the following moment of momentum equations about O is CORRECT and canbe used to solve for the angular velocity of rod OA?A. mgVBo(0.9) = MBVB1(0.9) + laAwOA1+moA(0.6@OA1)(0.3)mgVBo (0.9) = mgVB1(0.9) + moA(0.3w0A1)(0.3)mgVBo (0.9)MBVB1(0.9) + IOAWOA1 + moA(0.3w0A1)C.D. mgVBo(0.9) = mgVB1(0.9) + IOAWOA1 + moA(0.3WOA1)(0.3)4. What is the impulse exerted by rod OA on block B?B. A 3-kg rod OA is initially hanging verticallywhen a 0.6 kg block B, sliding on ahorizontal surface with negligible frictionwith a velocity of veo= 3.2m/s, strikes therod at its end A.1. If the blocks velocity after the impactis ve1 = 0.16 m/s what is thecoefficient of restitution betweenblock B and bar OA?VвоAB2. Which of the following is the most ideally constructed momentum-impulse diagram forthe system of block B and bar OA together?RoatO o+G%3DB.GA.moverma%3Dmaermava0.3 m0.9 m

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Answered: A 3-kg rod OA is initially hanging…

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