Need help with parts (d) and (e). Answers to (a), (b), and (c) are 40 m/s, -72 Ns, and 72 Ns, respectively. # ImpactA bullet of mass 200 g is traveling horizontally due east with a speed of 400 m/s when it strikes a block of mass 1.8 kg that is initially at rest on a smooth table. After striking the block, the bullet is embedded in the block and the two objects move together as one unit.### Questions:(a) What is the magnitude and direction of the velocity of the block/bullet combination immediately after impact?(b) What is the magnitude and direction of the impulse from the block to the bullet?(c) What is the magnitude and direction of the impulse from the bullet to the block?(d) If it took 3 ms for the bullet to decelerate from 400 m/s to the final speed after impact, what was the average force between the block and the bullet during this time?(e) If it took 3 ms for the block to accelerate to the final speed after impact, what was the average force between the bullet and the block during this time?

Given, mass of bullet , mbullet = 200g = 0.2 kg mass of block , mblock = 1.8 kg From part A) velocity of block/bullet combination = 40m/sD) Initial speed = 400m/s Final speed = 40m/s Time = 3 ms =3×10-3 s acceleration = Final velocity - Initial velocitytime =40m/s-400m/s3×10-3 s =-120000 m/s2 Average force = ma = 0.2kg×120000 m/s2 =24000 N E) Initial speed = 0m/s Final speed = 40m/s Time = 3 ms =3×10-3 s acceleration = Final velocity - Initial velocitytime =40m/s-0m/s3×10-3 s =13333.33 m/s2 Average force = ma = 1.8kg×13333.33 m/s2 =24000 N