**Titration Example: Trimethylamine with Hydrobromic Acid**A 28.4 mL sample of 0.379 M trimethylamine, \((CH_3)_3N\), is titrated with 0.318 M hydrobromic acid.At the titration midpoint, the pH is \(\_\_\_\_\_\). ---**Explanation:**This example involves the titration of a weak base, trimethylamine, with a strong acid, hydrobromic acid. During a titration, the base reacts with the acid to form a salt and water.- **Titration Midpoint:** The point at which half of the acid (or base) needed to reach the equivalence point has been added. At this point, the concentration of the weak base is equal to the concentration of its conjugate acid, and the pH can be calculated using the pKa of the conjugate acid.Note: No graphs or diagrams are included in this example.

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A 28.4 mL sample of 0.379 M trimethylamine, (CH3)3N, is titrated with 0.318 M hydrobromic acid. At the titration midpoint, the pH is

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Titration Example: Trimethylamine with Hydrobromic Acid**

A 28.4 mL sample of 0.379 M trimethylamine, \((CH_3)_3N\), is titrated with 0.318 M hydrobromic acid.

At the titration midpoint, the pH is \(\_\_\_\_\_\).

---
**Explanation:**

This example involves the titration of a weak base, trimethylamine, with a strong acid, hydrobromic acid. During a titration, the base reacts with the acid to form a salt and water.

- **Titration Midpoint:** The point at which half of the acid (or base) needed to reach the equivalence point has been added. At this point, the concentration of the weak base is equal to the concentration of its conjugate acid, and the pH can be calculated using the pKa of the conjugate acid.

Note: No graphs or diagrams are included in this example.

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