A +25.0µC point charge is placed 6.0 cm from an identical +25.0µC_point charge. How much work would be required by an external force to move a +18.0µC test charge from a point midway between them to a point 1.0 cm closer to either of the charges.
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- There are three point charges in a system. The first is -2.9uC and is located at (0,0.4) m. The second is 3.29uC and is located at (85.9,0) m. The third is -9.83uC and is located at (86.4,50.4) m. What is the potential (in V) at the origin due to these three charges?Two point charges (nC and -15.50 nC) are located 8.00 cm apartLet U = 0 when all of the charges are separated by infinite distances. What is the potential energy if a third point charge q = - 4.2nC is placed at point b?Given two particles with Q = 2.80-μC charges as shown in the figure below and a particle with charge q = 1.27 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞o.) 9 x = -0.800 m 0 x = 0.800 m x (a) What is the net force (in N) exerted by the two 2.80-μC charges on the charge q? (Enter the magnitude.) N (b) What is the electric field (in N/C) at the origin due to the two 2.80-μC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.80-μC particles? kv (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.80-μC particles? J
- An immovable charge Q₁ = +2.0µC is placed in fixed location at the origin on an (x, y) coordinate system. Another charge, Q₂ = +4.0μC is allowed to move near the first charge. How much work does it take to move this charge from it's starting location of (-3cm, 4cm) to the following locations and if the time to make this change is 10 ms how much power was output during each process: (a) (-1.5cm, 2cm) (b) (-6cm, 8cm) (c) (3cm, 4cm)There are three point charges in a system. The first is 5.73 MicroC and is located at (0,-19.5) m. The second is 2.63 MicroC and is located at (-24.7,0) m. The third is 9.54 MicroC and is located at (-74.8,-87.4) m. What is the potential (in V) at the origin due to these three charges?A point charge q1 = 4.69 x 10-6 C is held fixed at the origin of a coordinate system. A second charge q2 = -3.16 x 10-6 C is initially at the %3D coordinates (0.149, 0) m and is then moved to the coordinates (0.215, 0) m. What change in potential energy results from moving q2?
- Given two particles with Q= 2.70-μC charges as shown in the figure below and a particle with charge q = 1.31 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞o.) Q x = -0.800 m 0 x = 0.800 m x Ⓡ (a) What is the net force (in N) exerted by the two 2.70-μC charges on the charge q? (Enter the magnitude.) N (b) What is the electric field (in N/C) at the origin due to the two 2.70-μC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.70-μC particles? kv (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.70-μC particles? JTwo point charges, A & B (qA =-80 μС & qв = 736 μC), are separated by an unknown distance. The distance between A & P is 28 cm. The potential at point P (see below) is zero. Determine the distance between A & B. P A B + 28 cm ? distance between A & B = -0.0003198 C × Dimensionally incorrect. Please check the type or dimension of your unit.