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Two point charges (+15.50 nC and -15.50 nC) are located 8.00 cm apart. Let U = 0 when all of the charges are separated by infinite distances. What is the potential energy if a third point charge q = -4.20 nC is placed at point b? 8.00 cm 8.00 cm b -4.00-4.00-4.00- cm cm cm Return to questi 27.02 µJ

Two point charges (+15.50 nC and -15.50 nC) are located 8.00 cm apart. Let U = 0 when all of the charges are separated by infinite distances. What is the potential energy if a third point charge q = -4.20 nC is placed at point b? 8.00 cm 8.00 cm b -4.00-4.00-4.00- cm cm cm Return to questi 27.02 µJ

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Two point charges (nC and -15.50 nC) are located 8.00 cm apartLet U = 0 when all of the charges are separated by infinite distances. What is the potential energy if a third point charge q = - 4.2nC is placed at point b?
**Question 11:** Two point charges (+15.50 nC and -15.50 nC) are located 8.00 cm apart. Let \( U = 0 \) when all of the charges are separated by infinite distances. What is the potential energy if a third point charge \( q = -4.20 nC \) is placed at point b? **Graph/Diagram Explanation:** The diagram shows three points arranged in a triangular configuration. - The two original point charges, +15.50 nC and -15.50 nC, are positioned 8.00 cm apart horizontally. - Point "a" is located at the position of the +15.50 nC charge on the left. - Point "b" is located directly in the middle of the 8.00 cm separation of the two original charges, vertically 8.00 cm above the line joining the original two charges. The diagram includes the following distances and positions: - \( a \leftrightarrow b \): 8.00 cm (upward) - \( a \leftrightarrow \text{center} \): 4.00 cm - \( \text{center} \leftrightarrow b \): 4.00 cm (upward) - \( \text{center} \leftrightarrow \text{right point} \): 4.00 cm - The total distance from the left point to the right point is 8.00 cm. An answer is provided in the diagram, boxed in red: \( 27.02 \, \mu J \), indicating the calculated potential energy. **Answer:** \( 27.02 \, \mu J \)
Transcribed Image Text:**Question 11:** Two point charges (+15.50 nC and -15.50 nC) are located 8.00 cm apart. Let \( U = 0 \) when all of the charges are separated by infinite distances. What is the potential energy if a third point charge \( q = -4.20 nC \) is placed at point b? **Graph/Diagram Explanation:** The diagram shows three points arranged in a triangular configuration. - The two original point charges, +15.50 nC and -15.50 nC, are positioned 8.00 cm apart horizontally. - Point "a" is located at the position of the +15.50 nC charge on the left. - Point "b" is located directly in the middle of the 8.00 cm separation of the two original charges, vertically 8.00 cm above the line joining the original two charges. The diagram includes the following distances and positions: - \( a \leftrightarrow b \): 8.00 cm (upward) - \( a \leftrightarrow \text{center} \): 4.00 cm - \( \text{center} \leftrightarrow b \): 4.00 cm (upward) - \( \text{center} \leftrightarrow \text{right point} \): 4.00 cm - The total distance from the left point to the right point is 8.00 cm. An answer is provided in the diagram, boxed in red: \( 27.02 \, \mu J \), indicating the calculated potential energy. **Answer:** \( 27.02 \, \mu J \)
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