A 240V, dc shunt motor with an armature circuit resistance of 0.10 runs at 850rpm when the armature current is measured to be 70A. It is intended to reduce the speed to 650rpm whereby the armature current will be 50A. This is achieved by placing an additional resistor in series with the armature resistance. Find the value of the resistance required to achieve that, when k = pZ = 233. 60A

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A 240V, dc shunt motor with an armature circuit resistance of 0.10 runs at 850rpm
when the armature current is measured to be 70A. It is intended to reduce the speed
to 650rpm whereby the armature current will be 50A. This is achieved by placing an
additional resistor in series with the armature resistance. Find the value of the
resistance required to achieve that, when k =
pZ
= 233.
60A
Transcribed Image Text:A 240V, dc shunt motor with an armature circuit resistance of 0.10 runs at 850rpm when the armature current is measured to be 70A. It is intended to reduce the speed to 650rpm whereby the armature current will be 50A. This is achieved by placing an additional resistor in series with the armature resistance. Find the value of the resistance required to achieve that, when k = pZ = 233. 60A
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