A 230-m length of wire stretches between two towers and carries a 155-A current. Determine the magnitude of the force on the wire due to the Earth's magnetic field of 5.0 x 10 T which makes an angle of 70 with the wire. Express your answer to two significant figures and include the appropriate units. µA ? F = Value Units
A 230-m length of wire stretches between two towers and carries a 155-A current. Determine the magnitude of the force on the wire due to the Earth's magnetic field of 5.0 x 10 T which makes an angle of 70 with the wire. Express your answer to two significant figures and include the appropriate units. µA ? F = Value Units
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Question 1
![**Problem Statement:**
A 230-m length of wire stretches between two towers and carries a 155-A current. Determine the magnitude of the force on the wire due to the Earth's magnetic field of \(5.0 \times 10^{-5} \, \text{T}\) which makes an angle of \(70^\circ\) with the wire.
*Express your answer to two significant figures and include the appropriate units.*
**Answer Box:**
\( F = \)
| Value | Units |
|-------|-------|
| | |
[Submit] [Request Answer]
**Explanation:**
You need to calculate the magnetic force on a current-carrying wire using the formula:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]
where:
- \( F \) is the magnetic force,
- \( I = 155 \, \text{A} \) is the current,
- \( L = 230 \, \text{m} \) is the length of the wire,
- \( B = 5.0 \times 10^{-5} \, \text{T} \) is the magnetic field strength, and
- \(\theta = 70^\circ\) is the angle between the wire and the magnetic field.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F592c3157-16ae-4adf-9e37-2db2ec2ebc8f%2F94122515-442f-4f7e-aa9e-b9c3dd3345d7%2Fj9hojc_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A 230-m length of wire stretches between two towers and carries a 155-A current. Determine the magnitude of the force on the wire due to the Earth's magnetic field of \(5.0 \times 10^{-5} \, \text{T}\) which makes an angle of \(70^\circ\) with the wire.
*Express your answer to two significant figures and include the appropriate units.*
**Answer Box:**
\( F = \)
| Value | Units |
|-------|-------|
| | |
[Submit] [Request Answer]
**Explanation:**
You need to calculate the magnetic force on a current-carrying wire using the formula:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]
where:
- \( F \) is the magnetic force,
- \( I = 155 \, \text{A} \) is the current,
- \( L = 230 \, \text{m} \) is the length of the wire,
- \( B = 5.0 \times 10^{-5} \, \text{T} \) is the magnetic field strength, and
- \(\theta = 70^\circ\) is the angle between the wire and the magnetic field.
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