A 216 Po nucleus undergoes alpha decay according to the reaction Po → Pb + He. Determine the following. (Let the atomic mass of Po be 216.0019 u, the atomic mass of Pb be 211.9919 u and the atomic mass of He be 4.0026 u.) 82 (a) Q value (in MeV) for the process (Enter your answer to at least two decimal places.) MeV (b) Kinetic energy (in MeV) of the alpha particle after the decay (Enter your answer to at least two decimal places.) MeV (c) Kinetic energy (in MeV) of the daughter nucleus after the decay Mev

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Chapter1: Units, Trigonometry. And Vectors
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4
216
A
Po nucleus undergoes alpha decay according to the reaction
216
Ро >
84
216
Po be 216.0019 u, the atomic
212
Pb + He. Determine the following. (Let the atomic mass of
82
84
2
84
212
4
mass of
Pb be 211.9919 u and the atomic mass of He be 4.0026 u.)
82
2
(a) Q value (in MeV) for the process (Enter your answer to at least two decimal places.)
MeV
(b) Kinetic energy (in MeV) of the alpha particle after the decay (Enter your answer to at least two decimal places.)
MeV
(c)
Kinetic energy (in MeV) of the daughter nucleus after the decay
MeV
Transcribed Image Text:4 216 A Po nucleus undergoes alpha decay according to the reaction 216 Ро > 84 216 Po be 216.0019 u, the atomic 212 Pb + He. Determine the following. (Let the atomic mass of 82 84 2 84 212 4 mass of Pb be 211.9919 u and the atomic mass of He be 4.0026 u.) 82 2 (a) Q value (in MeV) for the process (Enter your answer to at least two decimal places.) MeV (b) Kinetic energy (in MeV) of the alpha particle after the decay (Enter your answer to at least two decimal places.) MeV (c) Kinetic energy (in MeV) of the daughter nucleus after the decay MeV
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