A = 21 131 122 2 2 2 = 2 0 -1 2 -2 0 500 010 001 118 - 100 I −14 118 -14 I 300-14 - 12
A = 21 131 122 2 2 2 = 2 0 -1 2 -2 0 500 010 001 118 - 100 I −14 118 -14 I 300-14 - 12
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

Transcribed Image Text:Matrix A is factored in the form PDP Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace.
1
4
A =
221
13 1
122
2 2 2
2 0 - 1
2-2 0
500
01
001
1
8
1
8
1
4
1
4
1
8
3
8
1
1
2 4
Select the correct choice below and fill in the answer boxes to complete your choice.
(Use a comma to separate vectors as needed.)
OA. There is one distinct eigenvalue, λ =
O B. In ascending order, the two distinct eigenvalues are ₁ =
OC. In ascending order, the three distinct eigenvalues are ₁ =₁^₂=
{}, respectively.
A basis for the corresponding eigenspace is { }.
and 2₂
=
Bases for the corresponding eigenspaces are { } and { }, respectively.
{1},{1}, and
and 23. Bases for the corresponding eigenspaces are
=
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