A 206.0-2 resistor and a 2.80-µF capacitor are connected in series across the terminals of a sinusoidal emf with a frequency of 150Hz. The inductance of the circuit is negligible. What is the impedance of the circuit?Ω

Answered: A 206.0-2 resistor and a 2.80-µF…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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A 206.0-2 resistor and a 2.80-µF capacitor are connected in series across the terminals of a sinusoidal emf with a frequency of 150
Hz. The inductance of the circuit is negligible. What is the impedance of the circuit?
Ω

Expert Solution

Step 1

$F r o m t h e q u e s t i o n, i t i s g i v e n t h a t R e s i s \tan c e (R) = 206 Ω C a p a c i \tan c e (C) = 2.80 μ F I n d u c \tan c e (L) = 0 H F r e q u e n c y (f) = 150 H z W e k n o w t h a t i m p e d e n c e Z = R + j X Z = R + (- j X) R = 206 Ω X = R e a c \tan c e = X_{c} o r X_{c} = \frac{1}{ω_{c}} X_{c} = \frac{1}{2 π f \times 2.80 \times 10^{- 6}} X_{c} = \frac{1}{2 π \times 150 \times 2.80 \times 10^{- 6}} X_{c} = 378.94 Ω$

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