A 20.00 mL sample of vinegar was titrated with 1.00 M NaOH. If it took 15.00 mL of NaOH to reach the equivalence or stoichiometric point, what is the mass percent of acetic acid (CH₂CO₂H) in the vinegar? Assume the density of vinegar is 1.00 g/mL. CH3CO₂H+ NaOH → H₂O+CH₂CO₂Na 9.00 % 9.0 % 4.50% 4.5 %

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Chapter4: Types Of Chemical Reactions And Solution Stoichiometry
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A 20.00 mL sample of vinegar was titrated with 1.00 M NaOH. If it took 15.00 mL of NaOH to reach the equivalence or
stoichiometric point, what is the mass percent of acetic acid (CH³COH) in the vinegar? Assume the density of
vinegar is 1.00 g/mL.
9.00 %
9.0 %
4.50%
4.5 %
CH3CO₂H+ NaOH → H₂O +CH₂CO₂Na
Transcribed Image Text:A 20.00 mL sample of vinegar was titrated with 1.00 M NaOH. If it took 15.00 mL of NaOH to reach the equivalence or stoichiometric point, what is the mass percent of acetic acid (CH³COH) in the vinegar? Assume the density of vinegar is 1.00 g/mL. 9.00 % 9.0 % 4.50% 4.5 % CH3CO₂H+ NaOH → H₂O +CH₂CO₂Na
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