A 20-year-old female presents to the emergency room of a large city hospital complaining of extreme abdominal pain and vaginal bleeding. Upon examination, no lesions are noted in her vaginal tract and the urinalysis does not indicate any sings of a urinary tract infection. Her admitting diagnosis is pelvic inflammatory disease (PID). The most likely cause is: Chlamydia trachomatis O herpes virus O HIV O Trichomonas vaginalis O Escherichia coli

A 20-year-old female presents to the emergency room of a large city hospital complaining of extreme abdominal pain and vaginal bleeding. Upon examination, no lesions are noted in her vaginal tract and the urinalysis does not indicate any sings of a urinary tract infection. Her admitting diagnosis is pelvic inflammatory disease (PID). The most likely cause is: Chlamydia trachomatis O herpes virus O HIV O Trichomonas vaginalis O Escherichia coli

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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Microbiology question. Please choose the right answers.

Study of lifeforms too small to see with the naked eye, including bacteria, viruses and protozoans. Microbiologists may study bacteria, yeast, or other microbes to understand better their reproduction, life cycle, or role in causing disease.

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Case Study: You are asked to inoculate lactose media (broth) with E. coli that was growing exponentially in glucose media (broth). You monitor the growth of these cells in the lactose broth using a viable plate count technique and plot the Growth Curve for E. coli growing c lactose. After a day of monitoring the cells, you note that the culture entered into lag phase growth initially and is now currently growing exponentially. In addition, you find that the cultures doubling time is 30 minutes. You know that the doubling time of E. coli in glucose media is 20 minutes. You did not change the oxygen content or temperature at Which you were growing the cells, E. coli is still aerobically respiring at 37°C. Question: If the lac operon is 'on' what does this imply about the cell? O The cell is dying and the lac operon is going to induce apoptosis. Apoptosis is truly cell death and the cells will enter into the death phase of the Growth Curve. O Lactose is being catabolized and glucose is no…