A 2.9-cm-diameter parallel-plate capacitor has a 1.5 mm spacing. The electric field strength inside the capacitor is 9.0x104 V/m. Part A What is the potential difference across the capacitor? Express your answer with the appropriate units. ▸ View Available Hint(s) AVC-135 V Submit Previous Answers 50 Part B Correct MODEL: The electric potential difference between the plates is determined by the uniform electric field in the parallel-plate capacitor. SOLVE: The potential difference AVc across a capacitor of spacing d is related to the electric field inside by E=AVC AVC=Ed=(9.0 × 10 V/m)(1.5 × 103 m) = 140 V How much charge is on each plate? Express your answer with the appropriate units. ▸ View Available Hint(s) Q- Value A Units Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining 44 D-II $ % 3 4 5 6 7 8 9 W E R T Y U о { P D F G H J K L x C v B N M H command ? x option F12 ] delete

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter8: Capacitance
Section: Chapter Questions
Problem 53P: A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when...
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A 2.9-cm-diameter parallel-plate capacitor has a
1.5 mm spacing. The electric field strength inside the
capacitor is 9.0x104 V/m.
Part A
What is the potential difference across the capacitor?
Express your answer with the appropriate units.
▸ View Available Hint(s)
AVC-135 V
Submit Previous Answers
50
Part B
Correct
MODEL: The electric potential difference between the plates is determined by the uniform electric field in the parallel-plate
capacitor.
SOLVE: The potential difference AVc across a capacitor of spacing d is related to the electric field inside by
E=AVC AVC=Ed=(9.0 × 10 V/m)(1.5 × 103 m) = 140 V
How much charge is on each plate?
Express your answer with the appropriate units.
▸ View Available Hint(s)
Q- Value
A
Units
Submit Previous Answers Request Answer
X Incorrect; Try Again; 4 attempts remaining
44
D-II
$
%
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4
5
6
7
8
9
W
E
R
T
Y
U
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{
P
D
F
G
H
J
K
L
x
C
v
B
N
M
H
command
?
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F12
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delete
Transcribed Image Text:A 2.9-cm-diameter parallel-plate capacitor has a 1.5 mm spacing. The electric field strength inside the capacitor is 9.0x104 V/m. Part A What is the potential difference across the capacitor? Express your answer with the appropriate units. ▸ View Available Hint(s) AVC-135 V Submit Previous Answers 50 Part B Correct MODEL: The electric potential difference between the plates is determined by the uniform electric field in the parallel-plate capacitor. SOLVE: The potential difference AVc across a capacitor of spacing d is related to the electric field inside by E=AVC AVC=Ed=(9.0 × 10 V/m)(1.5 × 103 m) = 140 V How much charge is on each plate? Express your answer with the appropriate units. ▸ View Available Hint(s) Q- Value A Units Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining 44 D-II $ % 3 4 5 6 7 8 9 W E R T Y U о { P D F G H J K L x C v B N M H command ? x option F12 ] delete
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