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A 2.850x10-2 M solution of glycerol (C3H₂O₂) in water is at 20.0°C. The sample was created by dissolving a sample of Ca H. Os in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.8 mL.. The density of water at 20.0°C is 0.9982 g/mL. Part A Calculate the molality of the glycerol solution. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) for Hit for Para Noo for Part redo foart Aroor Part A keyboard shortcuts for Part A help for Part A M mco,-2.9-10-2 Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Part B Calculate the mole fraction of glycerol in this solution. Express the mole fraction to four significant figures. View Available Hint(s) for Part R Puto for Part redo fort B or Part B keyboard shortcuts for Part B help for Part B

A 2.850x10-2 M solution of glycerol (C3H₂O₂) in water is at 20.0°C. The sample was created by dissolving a sample of Ca H. Os in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.8 mL.. The density of water at 20.0°C is 0.9982 g/mL. Part A Calculate the molality of the glycerol solution. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) for Hit for Para Noo for Part redo foart Aroor Part A keyboard shortcuts for Part A help for Part A M mco,-2.9-10-2 Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Part B Calculate the mole fraction of glycerol in this solution. Express the mole fraction to four significant figures. View Available Hint(s) for Part R Puto for Part redo fort B or Part B keyboard shortcuts for Part B help for Part B

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 2.850x10-² M solution of glycerol (C3H8O3) in water is at 20.0°C. The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.8 mL. The density of water at 20.0°C is 0.9982 g/mL. Part A Calculate the molality of the glycerol solution. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) mc,H,O, 2.9. 10 Submit Part B XC₂₂ Submit X Incorrect; Try Again; 4 attempts remaining Part C for Phirt A for Party Calculate the mole fraction of glycerol in this solution. Express the mole fraction to four significant figures. ▸ View Available Hint(s) Previous Answers Submit Part D Ndo for Part percent by mass C3H8O3 = M Submit Calculate the concentration of the glycerol solution in percent by mass. Express your answer to four significant figures and include the appropriate units. ▸ View Available Hint(s) for Part B for Parte do for Part redo foart Bre e redo for Part A resor Part A keyboard shortcuts for Part A help for Part A Value parts per million by mass C₂ H₂O3 = for Rart C for Part Cdo for Part redo forart Cres or Part B keyboard shortcuts for Part B help for Part B Units Calculate the concentration of the glycerol solution in parts per million by mass. Express your answer as an integer to four significant figures and include the appropriate units. ▸ View Available Hint(s) Value Part C keyboard shortcuts for Part C help for Part C for Rayt D for Part Ddo for Part redo forart D res Units Review | Constants I Periodic Table Part D keyboard shortcuts for Part D help for Part D
Transcribed Image Text:A 2.850x10-² M solution of glycerol (C3H8O3) in water is at 20.0°C. The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.8 mL. The density of water at 20.0°C is 0.9982 g/mL. Part A Calculate the molality of the glycerol solution. Express your answer to four significant figures and include the appropriate units. View Available Hint(s) mc,H,O, 2.9. 10 Submit Part B XC₂₂ Submit X Incorrect; Try Again; 4 attempts remaining Part C for Phirt A for Party Calculate the mole fraction of glycerol in this solution. Express the mole fraction to four significant figures. ▸ View Available Hint(s) Previous Answers Submit Part D Ndo for Part percent by mass C3H8O3 = M Submit Calculate the concentration of the glycerol solution in percent by mass. Express your answer to four significant figures and include the appropriate units. ▸ View Available Hint(s) for Part B for Parte do for Part redo foart Bre e redo for Part A resor Part A keyboard shortcuts for Part A help for Part A Value parts per million by mass C₂ H₂O3 = for Rart C for Part Cdo for Part redo forart Cres or Part B keyboard shortcuts for Part B help for Part B Units Calculate the concentration of the glycerol solution in parts per million by mass. Express your answer as an integer to four significant figures and include the appropriate units. ▸ View Available Hint(s) Value Part C keyboard shortcuts for Part C help for Part C for Rayt D for Part Ddo for Part redo forart D res Units Review | Constants I Periodic Table Part D keyboard shortcuts for Part D help for Part D
Part C A sucrose solution is prepared to a final concentration of 0.140 M. Convert this value into terms of g/L, molality, and mass %. (Use the following values: molecular weight MW sucrose = 342.296 g/mol; density Psol'n = 1.02 g/mL ; and mass of water, mwat=972.1 g). Note that the mass of solute is included in the density of the solution. Express the concentrations in grams per liter, molality, and mass percent to three significant figures separated by commas. ► View Available Hint(s) | Doto r o for Part redo for eart C restor Part C keyboard shortcuts for Part C help for Part C sucrose concentrations = 47.9,1.4410-4,4.93 Submit Previous Answers X Incorrect; Try Again; 2 attempts remaining for Part for Part Gravimetric analysis Gravimetric analysis is a technique by which information is obtained based on massed values. One application of gravimetric analysis can allow the solubility of a solid to be determined. This is achieved by adding a known mass of solid to solution, then collecting and massing the amount precipitated to discover how much had dissolved into a known then cross-referencing against a list of known solubility values. Part D To observe how such a technique works, select Potassium chromate as the solute in the PhET simulation. Slide both the Solute Amount and Solution Volume to the lowest possible values (0.00 mol and 0.20 L). Then, begin adding potassium chromate solute by sliding the Solute Amount scale bar upward. This represents adding solute to a solu precipitate. This precipitate can then be collected, dried, and massed. Then, by determining the difference between total mass and precipitated mass, the dissolved mass can be found. Dividing dissolved mass by solution volume would provide a usable concentration value that indicates solubility. solubility of PbCl₂ = Suppose 228.9 mg of PbCl₂ was added to 15.0 mL of water in a flask, and the solution was allowed to reach equilibrium at 20.0 °C. Some solute remained at the bottom of the flask after equilibrium, and the solution was filtered to collect the remaining PbCl₂, which had a mass of 76.4 mg. What is the solubility of PbCl₂ (in g/L)? Express the concentration in grams per liter to three significant figures. ► View Available Hint(s) Submit | Addo g/L, m, % for Part D for Part D vec for Part P redo for Part D res or Part D keyboard shortcuts for Part D help for Part D g/L
Transcribed Image Text:Part C A sucrose solution is prepared to a final concentration of 0.140 M. Convert this value into terms of g/L, molality, and mass %. (Use the following values: molecular weight MW sucrose = 342.296 g/mol; density Psol'n = 1.02 g/mL ; and mass of water, mwat=972.1 g). Note that the mass of solute is included in the density of the solution. Express the concentrations in grams per liter, molality, and mass percent to three significant figures separated by commas. ► View Available Hint(s) | Doto r o for Part redo for eart C restor Part C keyboard shortcuts for Part C help for Part C sucrose concentrations = 47.9,1.4410-4,4.93 Submit Previous Answers X Incorrect; Try Again; 2 attempts remaining for Part for Part Gravimetric analysis Gravimetric analysis is a technique by which information is obtained based on massed values. One application of gravimetric analysis can allow the solubility of a solid to be determined. This is achieved by adding a known mass of solid to solution, then collecting and massing the amount precipitated to discover how much had dissolved into a known then cross-referencing against a list of known solubility values. Part D To observe how such a technique works, select Potassium chromate as the solute in the PhET simulation. Slide both the Solute Amount and Solution Volume to the lowest possible values (0.00 mol and 0.20 L). Then, begin adding potassium chromate solute by sliding the Solute Amount scale bar upward. This represents adding solute to a solu precipitate. This precipitate can then be collected, dried, and massed. Then, by determining the difference between total mass and precipitated mass, the dissolved mass can be found. Dividing dissolved mass by solution volume would provide a usable concentration value that indicates solubility. solubility of PbCl₂ = Suppose 228.9 mg of PbCl₂ was added to 15.0 mL of water in a flask, and the solution was allowed to reach equilibrium at 20.0 °C. Some solute remained at the bottom of the flask after equilibrium, and the solution was filtered to collect the remaining PbCl₂, which had a mass of 76.4 mg. What is the solubility of PbCl₂ (in g/L)? Express the concentration in grams per liter to three significant figures. ► View Available Hint(s) Submit | Addo g/L, m, % for Part D for Part D vec for Part P redo for Part D res or Part D keyboard shortcuts for Part D help for Part D g/L
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