0.60 grams of a non electrolyte was dissolved in a total of 12.0 mL of water. The osmotic pressure of the solution was measured to be 7.55 atm at 25 °C. Determine the molecular mass of this non electrolyte. Possible useful information: . . . 0 R = 0.0821 Latm/K mol 07= MRT • PV = nRT

0.60 grams of a non electrolyte was dissolved in a total of 12.0 mL of water. The osmotic pressure of the solution was measured to be 7.55 atm at 25 °C. Determine the molecular mass of this non electrolyte. Possible useful information: . . . 0 R = 0.0821 Latm/K mol 07= MRT • PV = nRT

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

100%

0.60 grams of a non electrolyte was dissolved in a total of 12.0 mL of water.
• The osmotic pressure of the solution was measured to be 7.55 atm at 25 °C.
.
Determine the molecular mass of this non electrolyte.
• Possible useful information:
R 0.0821 L atm/K mol
R
.
• π = MRT
• PV = nRT
Psoln Posolvent Xsolvent
O
162 g/mol
33.0 g/mol
O 28.0 g/mol
81.0 g/mol
56.0 g/mol

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