A 2.50-m long pendulum is swung with an initial angle of 12.0⁰. a. How long does it take for the pendulum to reach its maximum speed? b. By the time the pendulum has swung 600 times, the angle formed by the pendulum with respect to the equilibrium position is 1/3 of the initial angle. What is the value of the quality factor of the pendulum?
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- One end of a string is attached to an object of mass M; When the object is raised to a position X that is a height H above its lowest point and released from rest, the object undergoes simple harmonic motion. When the object passes through the equilibrium position Y it has a speed of v. Which of the following methods could a student use to determine the total mechanical energy at Position Y & why. Select 2 answers. A.ME = KE - PE because energy changes from KE to PE when the pendulum swings from X to Y B.ME = PE - KE because energy changes from PE to KE when the pendulum swings from Y to X C.ME = KE because this represents the maximum KE at Y as the system has 0 PE at Y D.ME = PE because this equation represents the maximum PE at X if the system has zero PE at YOne end of a string is secured to the ceiling of a classroom, and the other end of the string is attached to a sphere of mass 0.20 kg so that a pendulum is established. The sphere is raised at an angle of 15° above the sphere’s equilibrium position and then released from rest so that the pendulum oscillates, as shown in the figure. Location 1 is shown in the figure. A graph of the pendulum’s horizontal position as a function of time is shown in the graph (the graph is in the attached image). a. Calculate the value of the maximum kinetic energy of the sphere as it oscillates The sphere is raised to a new angle above the sphere’s equilibrium position that is less than the angle described for part (a). The sphere is released from rest so that the pendulum oscillates. b. Explain how the motion of the sphere changes, if at all, based on the appropriate evidence and/or reasoning.An ideal spring hangs from the ceiling. A 2.15 kg mass is hung from the spring, stretching the spring a distance d = 0.0835 m from its original length when it reaches equilibrium. The mass is then lifted up a distance L = 0.0255 m from the equilibrium position and released. What is the kinetic energy K of the mass at the instant it passes back through the equilibrium position? K = J d Equilibrium position www. 14 L Co
- A 37 kg block on a horizontal frictionless surface is attached to a spring. The block is exhibiting SHM. The total energy of the system is 420 J. A.) Determine how much PE it has when its KE is six-sevenths of the PE. PE= w B.) Determine the maximum speed of the block. Vmax=A mass m = 3.3 kg is at the end of a horizontal spring on a frictionless horizontal surface. The mass is oscillating with an amplitude A = 4.5 cm and a frequency f = 1.5 Hz. a. Write an equation for the spring constant k. b. Calculate the spring constant k, in Newtons per meter. c. Write an equation for the total mechanical energy, E, of the motion. Your expression should be in terms of the variables in the original problem statement. d. Calculate the total mechanical energy E, in joules.A block of mass 1.80 kg is attached to an ideal spring with spring constant 340 N/m, and it oscillates on a frictionless surface. As it passes through its equilibrium position (spring is neither stretched or compressed), it’s moving at 12.0 m/s. Part A. What is the amplitude of the block's oscillation? Part B. What is the maximum acceleration of the block during its osciation?
- A simple pendulum is 0.44 m long. At t = 0 it is released from rest starting at an angle of 18°. Part A Ignoring friction, what will be the angular position of the pendulum at t = 0.35 s? Express your answer in degrees. ? 0.35 Submit Request Answer Part B Ignoring friction, what will be the angular position of the pendulum at t = 3.45 s? Express your answer in degrees. ηVM ΑΣφ 03.45 = Submit Request Answer Part C Ignoring friction, what will be the angular position of the pendulum at t = 6.00 s?A pendulum with a length of 0.75 m and a mass of 4 kg is swinging consistently swinging back and forth without losing any energy to its environment. The maximum velocity the pendulum can achieve is 2 m/s. Calculate the kinetic energy of the pendulum.Chapter 15, Problem 24 Z Your answer is partially correct. Try again. In the figure, two springs are joined and connected to a block of mass 40.3 kg that is set oscillating over a frictionless floor. The springs each have spring constant k = 242 N/m. What is the frequency (in Hz) of the oscillations? Number Units THz the tolerance is +/-2%
- An undamped 2.50 kg horizontal spring oscillator has a spring constant of 29.0 N/m. While oscillating, it is found to have a speed of 2.20 m/s as it passes through its equilibrium position. What is its amplitude of oscillation? What is the oscillator's total mechanical energy as it passes through a position that is 0.656 of the amplitude away from the equilibrium position?A pendulum is created with a string of length L, fixed at the top. A ball with mass m is fastened to the bottom. The ball is pulled to the side through an angle theta anrd released. What is the speed of the ball at lowest point? L=1.90 Theta=29.0 Mass=600kgAn ideal spring hangs from the ceiling. A 1.65 kg1.65 kg mass is hung from the spring, stretching the spring a distance ?=0.0925 md=0.0925 m from its original length when it reaches equilibrium. The mass is then lifted up a distance ?=0.0315 mL=0.0315 m from the equilibrium position and released. What is the kinetic energy of the mass at the instant it passes back through the equilibrium position?