Construct the influence line for the shear at point C. The x in the table is from point A. X2.5'AyEquation of Vc when unit load islocated at Segment AC:ľAAy = 1-A2.5'1X10CMVc7.5'CMsection = 0X10ΣMB = 0B1 (10-x) - Ay (10) = 0XByAy = 1-10Equation of Vc when unit load islocated at Segment CB:1↓M(₁-Vc +-(1--XVCAC10-) -1=0CVc +Msection=0X10X10VCcB += 1-7.5'VCB =-1=0XBy=BX10 Table:X02.5(AC)2.5 (CB)57.510Vc

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A 2.5' Ay Vc when unit load is egment AC: A Ay = 1- 2.5' C X 10 M 7.5' с Msection = 0 X 10 -Vc + - (1 - X 10 VCAC = MB = 0 1 (10-x) - Ay (10) = 0 X By Ay = 1- 10 Equation of Vc when unit load is located at Segment CB: 1 Į M C -) -1=0 C Vc + M section=0 X 10 VCB + VCB = 1- 7.5' -1=0 X 10 X B By= x 10

A 2.5' Ay Vc when unit load is egment AC: A Ay = 1- 2.5' C X 10 M 7.5' с Msection = 0 X 10 -Vc + - (1 - X 10 VCAC = MB = 0 1 (10-x) - Ay (10) = 0 X By Ay = 1- 10 Equation of Vc when unit load is located at Segment CB: 1 Į M C -) -1=0 C Vc + M section=0 X 10 VCB + VCB = 1- 7.5' -1=0 X 10 X B By= x 10

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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