A 2.25 g sample of an unknown gas at 29⁢ ∘C and 1.00 atm is stored in a 1.45 L flask. What is the density of the gas? and what is the molar mass?

Q: A 1.35 g sample of an unknown gas at 43 ∘C and 1.10 atm is stored in a 1.45 L flask. What is the…

A: The density is calculated by using given mass and volume.

Q: A 4.57 L container containing a mixture of gases has a temperature of 41.7 °C and a pressure of…

A:

Q: A 2.65 g2.65 g sample of an unknown gas at 73 ∘C73 ∘C and 1.00 atm1.00 atm is stored in a 2.75 L2.75…

A:

Q: A sample of xenon gas at a pressure of 955 mm Hg and a temperature of 39 °C, occupies a volume of…

A:

Q: An unknown gas at 67.1 ∘C and 1.05 atm has a molar mass of 28.01 g/mol. Assuming ideal behavior,…

A: We will is use ideal gas equation to get the density.

Q: molar mass

A:

Q: A sample of gas of mass 2.41 g occupies a volume of 480 mL  at 27 oC  and 0.14 atm pressure. What is…

A: Given information: mass = 2.41 g volume = 480 mL  Temperature = 27oC = 27+273.15 = 300.15 K…

Q: You start with an equimolar mixture of the gases SO₂ and O₂ in a container. The SO₂ and O₂ react to…

A: Ideal gas equation is given by PV=nRT where P is the pressure, V is the volume, n is the number of…

Q: Cyanogen, a highly toxic gas, is composed of 46.2% C and 53.8% N by mass. At 25 degrees C and 751…

A: Given:Mass percent composition of carbon is 46.2%.Mass percent composition of nitrogen is 53.8%. The…

Q: A gas mixture with a pressure of 1.31 atm is composed of 20.95g O, and 78.09g N2. What is the…

A: Given: Total pressure of gaseous mixture = 1.31 atm. Mass of O2 = 20.95 g. And mass of N2 = 78.09 g.…

Q: A 3.55 g sample of an unknown gas at 23 ∘C and 1.05 atm is stored in a 3.05 L flask. What is the…

A:

Q: 3.65 g3.65 g sample of an unknown gas at 75 ∘C75 ∘C and 1.00 atm1.00 atm is stored in a 1.95 L1.95 L…

A:

Q: A sample of an unknown gas weighing 10.9 g occupies a 25.585 L container at a pressure of 0.694 atm…

A: Given a sample of gas,mass of gas =10.9 gvolume of gas =25.585 Lpressure of gas =0.694 atmand…

Q: You start with an equimolar mixture of the gases SO2 and O2 in a container. The SO2 and O2 react to…

A: Given:         Temperature=25°CPressure=1.85 atmConversion:From Celsius to…

Q: A sample of a gas at 77°C and 1.33 atm occupies a volume of 50.3 L. How many moles of the gas are…

A: Given ,  Temperature =77°C =350K Pressure = 1.33 atm And volume =. 50.3 L

Q: A 1.95 g sample of an unknown gas at 61 ∘C and 1.00 atm is stored in a 1.45 L flask. What is the…

A: Given information:Mass of sample = 1.95 gTemperature = 61 °CPressure of gas = 1.00 atmVolume of…

Q: a sample of gas of mass 2.82g occupies a volume of 639mL at 27 degree celsiuse and 1.00 atm…

A: Given information: mass = 2.82 g volume = 639 mL  Temperature = 27oC = 27+273 = 300 K  Pressure =…

Q: A gaseous compound containing 62.45% chlorine and 37.55% nitrogen by mass are held at standard…

A:

Q: A 5.25g sample of gas occupies a volume of 1L and exerts a pressure of 1.074atm at -4 degree…

A: An ideal gas is represented by the following expression: PV = nRT    ............ (1) where P, V, n,…

Q: A 247 mL gas sample has a mass of 0.431 g at a pressure of 738 mmHg and a temperature of 26 ∘C.…

A:

Q: You start with an equimolar mixture of the gases SO₂ and O₂ in a container. The SO₂ and O₂ react to…

A: The reaction for the process is: 2SO2  +  O2  →  2SO3 We have equimolar mixture of SO2 and O2.…

Q: A 2.35 g2.35 g sample of an unknown gas at 29 ∘C29 ∘C and 1.05 atm1.05 atm is stored in a 2.25 L2.25…

A: According to ideal gas law PV = nRT where P = pressure = 1.05 atm (given) V = volume = 2.25 L…

Q: 3.55 g sample of an unknown gas at 33 degrees Celcius and 1.10 atm is stored in a 2.55 L flask. What…

A: The density of the gas present in the flask can be calculated by diving its mass by volume.

Q: A 4.17 g4.17 g sample of NH3NH3 gas and a 4.17 g4.17 g sample of HClHCl gas are mixed in a 2.00…

A: GIVEN: NH3 gas sample =  4.17 g HCl gas sample = 4.17g Volume of flask =2.00 L Temperature=25oC To…

Q: You start with an equimolar mixture of the gases SO, and O, in a container. The SO, and O, react to…

A:

Q: At 1.01 atm and 5.66 ∘C a 2.51 g sample of gas occupies a volume of 2430 mL. Calculate the molar…

A: Given,  pressure = 1.01 atm Volume = 2430 ml = 2.43 L  Mass of gas = 2.51 g Temperature = 56.6°C =…

Q: A 2.05 g sample of an unknown gas at 59 ∘C and 1.10 atm is stored in a 2.85 L flask. What is the…

A: Given,Mass of the sample = 2.05 gVolume is 2.85 LTemperature = 273.15 K + 59 = 33.152 KPressure =…

Q: What is the molar mass of the gas?

A: Given, Temperature = 0°C =273.15 KVolume = 426 mL = 0.426 LPressure = 1 atm Gas Law: PV = nRTP = mM…

Q: An unknown gas at 73.1 ∘C and 1.05 atm has a molar mass of 44.10 g/mol. Assuming ideal behavior,…

A: Ideal gas equation is the equation which obeys all gas laws under all condition of temperature and…

Q: A compound which is 39.9 % C, 13.5 % H, and 46.6 % N by mass was studied.  A 0.378 g sample of the…

A:

Q: A sample of gas of mass 3.82g occupies a volume of 539 mL at 27 ⁰ C and 1.0 atm pressure. What is…

A:

Q: A 3.65 g sample of an unknown gas at 61 ∘C and 1.00 atm is stored in a 2.05 L flask. What is the…

A:

Q: A 18.0 mg sample of an unknown gas is placed in a 750.0 mL flask at 85 0C and 1.20 atm. What is the…

A: Given data,Mass of gas=18.0mg=0.018gVolume=750mL=0.750LTemperature=85oC=85+273=358KPressure=1.2atm

Q: A 2.15 g2.15 g sample of an unknown gas at 59 ∘C59⁢ ∘C and 1.00 atm1.00 atm is stored in a 1.95…

A:

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.