**Pendulum and Collision Problem**A 2.0-kg pendulum ball is attached to a light, uniform cable of length 1.20 m, which hangs from the ceiling at an angle of 50.0° to the vertical. When the pendulum ball is released from this rest position, it swings to the lowest point of its motion. There, it collides head-on with a 1.4-kg block that is initially at rest on a level surface. If the pendulum ball's recoil speed is 1.50 m/s, what is the speed of the block after the collision?**Diagram Explanation:**- The diagram shows a pendulum system. - The pendulum consists of a 2.0-kg spherical ball attached to a string of length 1.2 m.- The cable forms an angle of 50° with the vertical when the pendulum is positioned at rest.- The pendulum swings downward and collides with a stationary 1.4-kg block on the level ground.**Possible Options for the Speed of the Block:**a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.75 m/s e. 3.03 m/s The task is to determine the speed of the block after the collision using principles of conservation of momentum and energy, considering the given conditions of the pendulum's release and collision.

Answered: Image /qna-images/answer/f8d9602c-df3d-4cd5-96d0-d7612d43510d.jpg

A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from the ceiling at an angle of 50.00 to the vertical. When the pendulum ball is released from the rest position. it swings to the very bottom of the motion where it collides head-on with a 1. 40-kg block that is initially at rest on a level surface. If the pendulum ball recolls at 1.50 m/s. what is the speed of the block after the collision? 6= 50° 1.2 m 2.0 kg 1,4 kg a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.76 m's e. 3.03 m/s

A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from the ceiling at an angle of 50.00 to the vertical. When the pendulum ball is released from the rest position. it swings to the very bottom of the motion where it collides head-on with a 1. 40-kg block that is initially at rest on a level surface. If the pendulum ball recolls at 1.50 m/s. what is the speed of the block after the collision? 6= 50° 1.2 m 2.0 kg 1,4 kg a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.76 m's e. 3.03 m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A spring with spring constant 20 N/m is compressed a distance of 5.5 cm by a ball with a mass of 208.5 g (see figure below). The ball is then released and rolls without slipping along a horizontal surface, leaving the spring at point A. The process is repeated, using a block instead, with a mass identical to that of the ball. The block compresses the spring by 5.5 cm and is also released, leaving the spring at point A. Each object travels up the incline shown in the figure before coming to rest momentarily. Assume the ball rolls, but ignore other effects of friction. (Assume the ball rolls without slipping up the incline until it comes to rest.) (a) How high above the starting position is the ball when it comes to rest momentarily? m (b) How high above the starting position is the block when it comes to rest momentarily? m
m A shown in the picture, a 238 g mass slides down a curved incline then collides with a spring. The spring constant of the spring is 106 N/m. Assume that friction is negligble in these problems. (A) If the mass starts from rest at a height of 1.97 cm, what is the final compression of the spring when the mass comes to rest? Assume the spring is initially uncompressed. 2.95 cm (B) If the mass initially compresses the spring 1.14 cm, what is the maximum height the mass rises to on the incline? Assume the mass is released from rest. (C) If the mass is released from rest at a height of 1.97 cm, what is the compression of the spring when the mass has a speed of 45.4 cm/s?
A ball of mass m, initially at rest, falls from a height h through a curved path to ground level (see figure). Then it is damped by a spring with a constant of elasticity k, until it stops. Using the law of conservation of mechanical energy, find the velocity of the ball just before it touches the spring and the distance the spring is compressed from its equilibrium length to when the ball stops.
The pendulum below consists of a bob of mass m in motion. During the motion, the supporting wire of length l maintains a constant angle θ with the vertical. Once it reaches the lowest point of the arc, use the conservation of energy (K1 + U1 = K2 +U2) to determine the following: a) Velocity of the bob in terms of g, L and θ b) Tension in the supporting wire in terms of m, g, and θ
A 5.00-gm projectile moving with an initial speed of 400. m/s is fired into and passes through a 1.00-kg block as shown. The block, initially stationary on a frictionless horizontal surface, is connected to a spring with a spring constant k = 900. N/m, If the block moves 5.00 cm to the right after impact find (a) the speed at which the projectile emerges from the block and (b) the energy lost in the collision. HINT: this is not an elastic or inelastic collision, but what concept can you use?
A cube of a mass m=0.37 kg is set against a spring with a spring constant of k1=656 N/m which has been compressed by a distance of 0.1 m. Some distance in front of it, along a frictionless surface, is another spring with a spring constant of k2=181N/m. The cube is not connected to the first spring and may slide freely. I found (a) and (b). I just need help with (c). a). How far d2, in meters, will the second spring compress when thee cube runs into it? 0.19 m. (answer) b). How fast v, in meters per second, will the cube be moving when it strikes the second spring? 4.21 m/s (answer) c). Now assume friction is present on the surface in between the ends of the springs at their equilibrium lengths, and the coefficient of kinetic friction is uk=0.5. If the distance between the springs is x=1m, how far d2, in meters, will the second spring now compress?
At sea level, at a latitude where g= 9.80 m/s^2, a pendulum that takes 3.00 s for a complete swing back and forth has a length of 2.24 m. What is the value of g in m/s2 at a location where the length of such a pendulum is 2.52 m? Question 13 options: 8.72 11.0 12.2 10.1 9.60
A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 23.0 N/m. The block rests on a frictionless surface. A 5.90×10−2-kg wad of putty is thrown horizontally at the block, hitting it with a speed of 8.96 m/s and sticking.How far does the putty-block system compress the spring?
OK, once again we have a pendulum, this time of length 1.49 m, which you release from rest at an angle of 41.6 degrees to the vertical. What will be the speed of the pendulum at the instant it reaches an angle of 12.5 degrees above the vertical? 4.08 m/s 2.58 m/s 2.72 m/s 0.83 m/s
An ideal spring of negligible mass with force constant of 400 N/m is placed on a frictionless horizonal table with one end fixed at a wall next to the table. A billiard ball of mass 200 g is pushed against the spring, compressing the spring to some distance. After the system is released, the spring returns to equilibrium with the billiard ball leaving the table’s edge at 4.00 m/s and hits the floor 80 cm below. Using the principle of energy conservation, (a) determine the initial compression of the spring. (b) What is the speed of the ball when it hits the floor?
A 0.35 kg mass is held against a compressed spring with a spring constant of 89 N/m. The mass is initially at rest upon a horizontal surface and the spring force is directed parallel to the plane of the surface. If the coefficient of kinetic friction is 0.86, with what speed does the mass leave contact with the spring if the spring is initially compressed by 0.232 m?
A 10.0 gg rifle bullet is fired with a speed of 350 m/s into a ballistic pendulum with mass 10.0 kg , suspended from a cord 70.0 cm long. Compute the initial kinetic energy of the bullet. Compute the kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum. Compute the vertical height through which the pendulum rises.