**Pendulum and Collision Problem**A 2.0-kg pendulum ball is attached to a light, uniform cable of length 1.20 m, which hangs from the ceiling at an angle of 50.0° to the vertical. When the pendulum ball is released from this rest position, it swings to the lowest point of its motion. There, it collides head-on with a 1.4-kg block that is initially at rest on a level surface. If the pendulum ball's recoil speed is 1.50 m/s, what is the speed of the block after the collision?**Diagram Explanation:**- The diagram shows a pendulum system. - The pendulum consists of a 2.0-kg spherical ball attached to a string of length 1.2 m.- The cable forms an angle of 50° with the vertical when the pendulum is positioned at rest.- The pendulum swings downward and collides with a stationary 1.4-kg block on the level ground.**Possible Options for the Speed of the Block:**a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.75 m/s e. 3.03 m/s The task is to determine the speed of the block after the collision using principles of conservation of momentum and energy, considering the given conditions of the pendulum's release and collision.

Answered: Image /qna-images/answer/f8d9602c-df3d-4cd5-96d0-d7612d43510d.jpg

A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from the ceiling at an angle of 50.00 to the vertical. When the pendulum ball is released from the rest position. it swings to the very bottom of the motion where it collides head-on with a 1. 40-kg block that is initially at rest on a level surface. If the pendulum ball recolls at 1.50 m/s. what is the speed of the block after the collision? 6= 50° 1.2 m 2.0 kg 1,4 kg a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.76 m's e. 3.03 m/s

A 2.00-kg pendulum ball is attached to a light-uniform cable of length 1.20 m that is hanging from the ceiling at an angle of 50.00 to the vertical. When the pendulum ball is released from the rest position. it swings to the very bottom of the motion where it collides head-on with a 1. 40-kg block that is initially at rest on a level surface. If the pendulum ball recolls at 1.50 m/s. what is the speed of the block after the collision? 6= 50° 1.2 m 2.0 kg 1,4 kg a. 5.98 m/s b. 3.88 m/s c. 6.29 m/s d. 4.76 m's e. 3.03 m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

Question

**Pendulum and Collision Problem**

A 2.0-kg pendulum ball is attached to a light, uniform cable of length 1.20 m, which hangs from the ceiling at an angle of 50.0° to the vertical. When the pendulum ball is released from this rest position, it swings to the lowest point of its motion. There, it collides head-on with a 1.4-kg block that is initially at rest on a level surface. If the pendulum ball's recoil speed is 1.50 m/s, what is the speed of the block after the collision?

**Diagram Explanation:**

- The diagram shows a pendulum system.
- The pendulum consists of a 2.0-kg spherical ball attached to a string of length 1.2 m.
- The cable forms an angle of 50° with the vertical when the pendulum is positioned at rest.
- The pendulum swings downward and collides with a stationary 1.4-kg block on the level ground.

**Possible Options for the Speed of the Block:**

a. 5.98 m/s
b. 3.88 m/s
c. 6.29 m/s
d. 4.75 m/s
e. 3.03 m/s

The task is to determine the speed of the block after the collision using principles of conservation of momentum and energy, considering the given conditions of the pendulum's release and collision.

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