A 2 diopter lens is placed behind a -3 diopter lens. There is an object 2 meter in front of the pair of lenses. How far from the lenses is the image
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A: height of firefly = 5.95 mm object distance (d) from lens A = 11.7 cm focal length of lens A = 5.61…
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A 2 diopter lens is placed behind a -3 diopter lens. There is an object 2 meter in front of the pair of lenses. How far from the lenses is the image?
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- an object of height 5 cm is placed 20 cm in front of a converging lens at focal length 10 cm. Behind the converging lens, and 25cm from it, there is a diverging lens of the focal length of 6 cm. Find the location of the final image, in centimeters, with respect to teh diverging lens. what is the magnification of the final image? what is the height of the final image?A 1 [cm] tall object is 50 [cm] away from a converging lens of focal length f = 30 [cm]. A second converging lens of focal length f = 80 [cm] is placed 2 [m] behind the first lens. a) Where is the image formed by the first lens (ignoring the second lens)? How big is it? b) Now, this image is the object for the second lens. Where is the second (final) image formed by the second lens? How big is it?It is your first day at work as a summer intern at an optics company. Your supervisor hands you a diverging lens and asks you to measure its focal length. You know that with a converging lens, you can measure the focal length by placing an object a distance ss to the left of the lens, far enough from the lens for the image to be real, and viewing the image on a screen that is to the right of the lens. By adjusting the position of the screen until the image is in sharp focus, you can determine the image distance s′s′ and then use the equation 1s+1s′=1f1s+1s′=1f, to calculate the focal length ff of the lens. But this procedure won't work with a diverging lens−−by itself, a diverging lens produces only virtual images, which can't be projected onto a screen. Therefore, to determine the focal length of a diverging lens, you do the following: First you take a converging lens and measure that, for an object 20.0 cmcm to the left of the lens, the image is 29.7 cmcm to the right of the lens.…
- An object is placed 25 cm in front of a converging lens of focal length 20 cm. 30 cm past the first lens is a second diverging lens of magnitude focal length 25 cm. What are the resulting image position relative to second lens and total magnification of the object in this setup?A 2.1-cm-tall object is 30 cm to the left of a lens with a focal length of 15 cm. A second lens with a focal length of -5 cm is 45 cm to the right of the first lens. Calculate the distance between the first image and the second lens. Calculate the image height.A diverging lens has a focal distance of f=0.2 cm. If an object is placed 0.1cm away, What is the image distance? Is the image real or virtual? What is the magnification?
- A fly appears to be upside down and 4 times its actual size when viewed through a converging lens with a focal length of 69 cm. How far is the fly from the lens?An object is placed in front of a diverging lens whose focal length is - 30.7 cm. A virtual image is formed whose height is 0.532 times the object height. How far is the object from the lens?A converging lens of focal length f=2 cm is used to focus the image of an object onto a screen. The object and screen are separated by 15 cm. The lens is placed between the object and the screen, at a distance from the screen such that the image of the object is focused into the screen. At what distance from the screen must the lens be placed in order to have an image magnification < 1? Provide your answer to two significant figures. distance = cm.