A 1m thick triangular soil block is shown below. Vertical dimension is H. The bottom face is inclined at e (radian) with horizontal. The weight of the block is W= y*area of the triangle*1; y = weight of the soil per unit volume. The resistance force along the bottom face of the block F = N*tan(o') + c*inclined length of the triangle at the bottom. N is the normal force at the bottom face of the block. o' = effective friction angle and c' = effective cohesion. A horizontal force P is set to keep the triangle from moving towards the left, and in equilibrium. Find an expression for P in terms of H, y, o', c' and e. Calculate P (kN) for H=5m, g=18 kN/m3, o'=30 deg, c'=0, and e = TT/4. Weight W P
A 1m thick triangular soil block is shown below. Vertical dimension is H. The bottom face is inclined at e (radian) with horizontal. The weight of the block is W= y*area of the triangle*1; y = weight of the soil per unit volume. The resistance force along the bottom face of the block F = N*tan(o') + c*inclined length of the triangle at the bottom. N is the normal force at the bottom face of the block. o' = effective friction angle and c' = effective cohesion. A horizontal force P is set to keep the triangle from moving towards the left, and in equilibrium. Find an expression for P in terms of H, y, o', c' and e. Calculate P (kN) for H=5m, g=18 kN/m3, o'=30 deg, c'=0, and e = TT/4. Weight W P
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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