A 1kg mass is attached to a spring (with spring constant k = 4 N/m), and the spring itself is attached to the ceiling. If you pull the mass down to stretch the spring past its equilibrium position, when you release the mass and observe its (vertical) position, it's said to undergo simple harmonic motion.
A 1kg mass is attached to a spring (with spring constant k = 4 N/m), and the spring itself is attached to the ceiling. If you pull the mass down to stretch the spring past its equilibrium position, when you release the mass and observe its (vertical) position, it's said to undergo simple harmonic motion.
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A 1kg mass is attached to a spring (with spring constant k = 4 N/m), and
the spring itself is attached to the ceiling. If you pull the mass down to stretch the
spring past its equilibrium position, when you release the mass and observe its
(vertical) position, it's said to undergo simple harmonic motion.
AT REST
MASS PULLED DOWN
Under certain initial conditions, the mass's vertical position (in metres) relative to its
equilibrium position at time t, y(t), can be modelled by the equation
y(t) = cos(2t) – sin(2t),
(Note that y measures how much the spring has been stretched, so y = 1 indicates
the mass is 1m below its equilibrium position, whereas y = -1 indicates it is 1m
above its equilibrium position.)
Find expressions for the mass's (vertical) velocity v(t) (relative to its
equilibrium position) and the mass's (vertical) acceleration a(t) (relative to its
equilibrium position).
Is the mass moving toward the ceiling or toward the floor at t = 7?
Justify your answer with a calculation.
At what time(s) in the first 2 seconds is the mass momentarily
stationary?
m
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