A 19.5 pm x-ray photon scatters off a free electron at A (see the figure below), producing a photon of wavelength A' traveling at an angle 0 = 43.0° relative to the first photon's direction. This second photon scatters off another free electron at B, producing a photon with wavelength " and moving in a direction directly opposite the first photon. Determine the wavelengths à' and λ", both in pm. HINT (a) A' (b) " pm pm Electron 1 Electron 2

icon
Related questions
Question
100%
**Interactive Compton Scattering Example**

A **19.5 pm** x-ray photon scatters off a free electron at point **A** (see the accompanying diagram), producing a photon with a wavelength **λ'** traveling at an angle **θ = 43.0°** relative to the original photon’s direction. Subsequently, this new photon scatters off another free electron at point **B**, producing a photon with a wavelength **λ''** that moves in a direction directly opposite to the first photon. Your task is to determine the wavelengths **λ'** and **λ''**, both measured in picometers (pm).

**Diagram Explanation:**

- **Initial Photon (λ):** An incoming photon with wavelength **λ** encounters an electron at point **A**.
- **Scattered Photon (λ'):** The photon, after interaction, changes direction at an angle **θ = 43.0°**, producing a wavelength **λ'**.
- **Electron 1:** The electron at **A** gains momentum and moves in a specific direction marked by the diagram.
- **Second Interaction at B:**
  - The photon with wavelength **λ'** interacts with another electron at point **B**.
  - A new photon with wavelength **λ''** is produced, moving opposite to the original photon’s direction.
- **Electron 2:** The electron at **B** moves in another distinct direction after the interaction.

**Parameters:**

- Initial angles, **α** and **β**, define electron scatter directions.

**Calculations Needed:**
- Solve for **(a) λ'** pm
- Solve for **(b) λ''** pm

**Hint:** Use Compton scattering formulas to find the changes in wavelength.
Transcribed Image Text:**Interactive Compton Scattering Example** A **19.5 pm** x-ray photon scatters off a free electron at point **A** (see the accompanying diagram), producing a photon with a wavelength **λ'** traveling at an angle **θ = 43.0°** relative to the original photon’s direction. Subsequently, this new photon scatters off another free electron at point **B**, producing a photon with a wavelength **λ''** that moves in a direction directly opposite to the first photon. Your task is to determine the wavelengths **λ'** and **λ''**, both measured in picometers (pm). **Diagram Explanation:** - **Initial Photon (λ):** An incoming photon with wavelength **λ** encounters an electron at point **A**. - **Scattered Photon (λ'):** The photon, after interaction, changes direction at an angle **θ = 43.0°**, producing a wavelength **λ'**. - **Electron 1:** The electron at **A** gains momentum and moves in a specific direction marked by the diagram. - **Second Interaction at B:** - The photon with wavelength **λ'** interacts with another electron at point **B**. - A new photon with wavelength **λ''** is produced, moving opposite to the original photon’s direction. - **Electron 2:** The electron at **B** moves in another distinct direction after the interaction. **Parameters:** - Initial angles, **α** and **β**, define electron scatter directions. **Calculations Needed:** - Solve for **(a) λ'** pm - Solve for **(b) λ''** pm **Hint:** Use Compton scattering formulas to find the changes in wavelength.
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Similar questions