A 18.2 g of iron metal reacts with excess oxygen gas to produce 47.9 g of Fe3O4. The reaction between these two substances are written as: ____ Fe(s) + ____ O2(g) → _____ Fe3O4 (s)Balance the chemical equation.Calculate the molar mass of O2 and Fe3O4.If the 43.72 g of Fe3O4 was produced, what is the percent yield of this reaction?

Given, mass of Iron = 18.2 g Amount of oxygen = excess mass of Fe3O4 = 47.9 g

Answered: A 18.2 g of iron metal reacts with…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A 18.2 g of iron metal reacts with excess oxygen gas to produce 47.9 g of Fe₃O₄. The reaction between these two substances are written as:

____ Fe_(s) + ____ O_2(g) → _____ Fe₃O_{4 (s)}

Balance the chemical equation.
Calculate the molar mass of O₂and Fe₃O₄.
If the 43.72 g of Fe₃O₄was produced, what is the percent yield of this reaction?

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