A 16.0-mm length of wire consists of 7.0 mm of copper followed by 9.0 mm of aluminum, both of diameter 1.4 mm. A voltage difference of 95 mV is placed across the composite wire. The resistivity of copper is 1.68×10−8Ω⋅m and the resistivity of aluminum is 2.65×10−8Ω⋅mWhat is the total resistance (sum) of the two wires?Express your answer to two significant figures and include the appropriate units.R total=What is the current through the wire?Express your answer to two significant figures and include the appropriate units.I= What is the voltage across the copper part?Express your answer to two significant figures and include the appropriate units.VCu= What is the voltage across the aluminum part?Express your answer to two significant figures and include the appropriate units.VWhat is the voltage across the aluminum part?Express your answer to two significant figures and include the appropriate units. What is the voltage across the aluminum part?Express your answer to two significant figures and include the appropriate units.VAl=

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Answered: A 16.0-mm length of wire consists of…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A 16.0-mm length of wire consists of 7.0 mm of copper followed by 9.0 mm of aluminum, both of diameter 1.4 mm. A voltage difference of 95 mV is placed across the composite wire. The resistivity of copper is 1.68×10−8Ω⋅m and the resistivity of aluminum is 2.65×10−8Ω⋅m

What is the total resistance (sum) of the two wires?