A 140 lb weight stretches a spring 14 feet. The weight hangs vertically from the spring and a damping forcenumerically equal to 5√√7 times the instantaneous velocity acts on the system. The weight is released from 7 feetabove the equilibrium position with a downward velocity of 30 ft/s.(a) Determine the time (in seconds) at which the mass passes through the equilibrium position.(b) Find the time (in seconds) at which the mass attains its extreme displacement from the equilibrium position.Round your answer to 4 decimals.Round your answer to 4 decimals.

Here, the weight of the spring is, W = 140 lbThe stretching of the spring due to the weight, x = 14…

Answered: A 140 lb weight stretches a spring 14…

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