A 13.00 kg particle starts from the origin at time zero. Its velocity as a function of time is given by = 10:²1 + 1tj where is in meters per second and t is in seconds. (Use the following as necessary: t.) (a) Find its position as a function of time. ŕ= 10 3 i+ (b) Describe its motion qualitatively. The particle starts from rest at the origin, starts moving in the y direction, and gains speed faster and faster while turning to move more and more nearly parallel to the x axis. Score: 0.06 out of 0.06 Comment: (c) Find its acceleration as a function of time. a=20ti + 1j m/s² (d) Find the net force exerted on the particle as a function of time. F= N T= x (e) Find the net torque about the origin exerted on the particle as a function of time. x N-m (f) Find the angular momentum of the particle as a function of time. C- kg-m²/s x
A 13.00 kg particle starts from the origin at time zero. Its velocity as a function of time is given by = 10:²1 + 1tj where is in meters per second and t is in seconds. (Use the following as necessary: t.) (a) Find its position as a function of time. ŕ= 10 3 i+ (b) Describe its motion qualitatively. The particle starts from rest at the origin, starts moving in the y direction, and gains speed faster and faster while turning to move more and more nearly parallel to the x axis. Score: 0.06 out of 0.06 Comment: (c) Find its acceleration as a function of time. a=20ti + 1j m/s² (d) Find the net force exerted on the particle as a function of time. F= N T= x (e) Find the net torque about the origin exerted on the particle as a function of time. x N-m (f) Find the angular momentum of the particle as a function of time. C- kg-m²/s x
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Chapter1: Units, Trigonometry. And Vectors
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![k
A 13.00 kg particle starts from the origin at time zero. Its velocity as a function of time is given by
= 10t² + 1tj
where is in meters per second and t is in seconds. (Use the following as necessary: t.)
V
(a) Find its position as a function of time.
ŕ=
esc
10/³1 + ²/2 2²;
3
(b) Describe its motion qualitatively.
The particle starts from rest at the origin, starts moving in the y direction, and
gains speed faster and faster while turning to move more and more nearly
parallel to the x axis.
Score: 0.06 out of 0.06
Comment:
(c) Find its acceleration as a function of time.
a = 20ti + lj
m/s²
(d) Find the net force exerted on the particle as a function of time.
F=
T=
(e) Find the net torque about the origin exerted on the particle as a function of time.
N m
X
X
(f) Find the angular momentum of the particle as a function of time.
Ľ
Need Help? Read It
F1
N
x
(g) Find the kinetic energy of the particle as a function of time.
K=
x
kg m²/s
X
(h) Find the power injected into the particle as a function of time.
P =
J
.
W
F2
2.0
F3
d
F4
%
F5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F166432ad-4ec6-485b-8e01-9903eb69478a%2Fe8ed81f2-d5e9-4b1f-99b2-e4b2db0f33ae%2Fv57v8i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:k
A 13.00 kg particle starts from the origin at time zero. Its velocity as a function of time is given by
= 10t² + 1tj
where is in meters per second and t is in seconds. (Use the following as necessary: t.)
V
(a) Find its position as a function of time.
ŕ=
esc
10/³1 + ²/2 2²;
3
(b) Describe its motion qualitatively.
The particle starts from rest at the origin, starts moving in the y direction, and
gains speed faster and faster while turning to move more and more nearly
parallel to the x axis.
Score: 0.06 out of 0.06
Comment:
(c) Find its acceleration as a function of time.
a = 20ti + lj
m/s²
(d) Find the net force exerted on the particle as a function of time.
F=
T=
(e) Find the net torque about the origin exerted on the particle as a function of time.
N m
X
X
(f) Find the angular momentum of the particle as a function of time.
Ľ
Need Help? Read It
F1
N
x
(g) Find the kinetic energy of the particle as a function of time.
K=
x
kg m²/s
X
(h) Find the power injected into the particle as a function of time.
P =
J
.
W
F2
2.0
F3
d
F4
%
F5
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