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A 125.0 mg sample of an unknown, monoprotic acid was dissolved in 100.0 mL of distilled water and titrated with a 0.050 M  solution of NaOH. The pH of the solution was monitored throughout the titration, and the data were collected in the table below. Determine the Ka of the acid and use the data table to identify the unknown acid.

A 125.0 mg sample of an unknown, monoprotic acid was dissolved in 100.0 mL of distilled water and titrated with a 0.050 M  solution of NaOH. The pH of the solution was monitored throughout the titration, and the data were collected in the table below. Determine the Ka of the acid and use the data table to identify the unknown acid.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.144QP
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  A 125.0 mg sample of an unknown, monoprotic acid was dissolved in 100.0 mL of distilled water and titrated with a 0.050 M  solution of NaOH. The pH of the solution was monitored throughout the titration, and the data were collected in the table below. Determine the Ka of the acid and use the data table to identify the unknown acid.
 

volume of OH- added (mL)                pH
0 3.09
5 3.65
10 4.10
15 4.50
17 4.55
18 4.71
19 4.94
20 5.11
21 5.37
22 5.93
22.2 6.24
22.6 9.91
22.8 10.2
23 10.4
24 10.8
25 11.0
30 11.5
40 11.8

 

Determine the Ka.  

 

Use the data table below to identify the name of the unknown acid.

 

 

Ka pKa
acetic 1
$$CH3​COOH(aq)+H2​O(l)H3​O+(aq)+CH3​COO−(aq)
 1.76x10-5 4.75
benzoic 1
$$C6​H5​COOH(aq)+H2​O(l)H3​O+(aq)+C6​H5​COO−(aq)
 6.25x10-5 4.20
formic 1
$$HCOOH(aq)+H2​O(l)H3​O+(aq)+HCOO−(aq)
 1.77x10-4 3.75
oxalic 1
$$HOOCCOOH(aq)+H2​O(l)H3​O+(aq)+HOOCCOO−(aq)
 5.9x10-2 1.23
  2
$$HOOCCOO−(aq)+H2​O(l)H3​O+(aq)+−OOCCOO−(aq)
 6.4x10-5 4.19
 
 
 
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