Given the ff. data below during a conductometric titration (strong acid vs strong base) Calculate the concentration (in molarity) of HCl and determine the equivalence point. HCl = 30 mL NaOH molarity = 0.111 M

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A: NOTE

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A: pKa = - log Ka  for weak acid pH = 12(pKa-logC) for salt hydrolysis: pH = 12[pKw + pKa + log C]

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A: The concentration of = The volume of HCl = The volume of =

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A: The reaction between acid and base is written below. 2C3H7COOH (aq) + Sr(OH)2 (aq) ⇌ 2H2O (l) +…

Q: The data for this homework assignment can be found her: Titration Curve Data.xlsx  Download…

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Q: Part D A 52.0-mL volume of 0.350 mol L-CH3COOH (Ka = 1.8 x 10-5 is titrated with 0.400 mol L-!N2OH.…

A:

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Q: 6. Calculate the pH of a solution during a titration of 2.5M HCI with 35mL of 1.25M NaOH A. 12mL of…

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A:

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Q: Part 2: Use the volume of NaOH used and the molarity of NaOH to calculate moles of NaOH reacted. Use…

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A: Point B is the correct answer.

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A: We have to answer questions 2, 3a. and 3b. For that, the data table given is:

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.