A 1200 kg car drives up a hill that is 15.2 m high. During the drive, two nonconservative forces do work on the car: (i) the force of friction, and (ii) the force generated by the car's engine. The work done by friction is -3.01×105 J ; the work done by the engine is 6.74x105 J. Part A Find the change in the car's kinetic energy from the bottom of the hill to the top of the hill. ? AK = J Submit Request Answer
A 1200 kg car drives up a hill that is 15.2 m high. During the drive, two nonconservative forces do work on the car: (i) the force of friction, and (ii) the force generated by the car's engine. The work done by friction is -3.01×105 J ; the work done by the engine is 6.74x105 J. Part A Find the change in the car's kinetic energy from the bottom of the hill to the top of the hill. ? AK = J Submit Request Answer
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Question 15**
A 1200 kg car drives up a hill that is 15.2 m high. During the drive, two nonconservative forces do work on the car: (i) the force of friction, and (ii) the force generated by the car's engine. The work done by friction is \(-3.01 \times 10^5 \, \text{J}\); the work done by the engine is \(6.74 \times 10^5 \, \text{J}\).
**Part A**
Find the change in the car’s kinetic energy from the bottom of the hill to the top of the hill.
\[
\Delta K = \underline{\quad\quad\quad} \, \text{J}
\]
[Submit] [Request Answer]
---
The problem involves calculating the change in kinetic energy of a car as it ascends a hill. Two main nonconservative forces are considered: friction, which does negative work, and the engine, which performs positive work on the car. The question requires finding the net change in kinetic energy based on these forces.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbe2dc1e3-fb5c-4361-9a35-12adea7e457d%2F16fe4891-6d1f-4676-a212-0f96ca8c16f4%2Famdffpk_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 15**
A 1200 kg car drives up a hill that is 15.2 m high. During the drive, two nonconservative forces do work on the car: (i) the force of friction, and (ii) the force generated by the car's engine. The work done by friction is \(-3.01 \times 10^5 \, \text{J}\); the work done by the engine is \(6.74 \times 10^5 \, \text{J}\).
**Part A**
Find the change in the car’s kinetic energy from the bottom of the hill to the top of the hill.
\[
\Delta K = \underline{\quad\quad\quad} \, \text{J}
\]
[Submit] [Request Answer]
---
The problem involves calculating the change in kinetic energy of a car as it ascends a hill. Two main nonconservative forces are considered: friction, which does negative work, and the engine, which performs positive work on the car. The question requires finding the net change in kinetic energy based on these forces.
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