A 12 V car battery dies not so much because its voltage drops but because chemical reactions increase its internal resistance. A good battery connected with jumper cables can both start the engine and recharge the dead battery. Consider the automotive circuit of (Figure 1). Figure 0.01 ΩΣ + 12 V 050 ΩΣ Jumpers Good battery 8V Dead battery 1 of 1 > 0.05 ΩΣ Starter motor ▼ Part A How much current could the good battery alone drive through the starter motor? Express your answer with the appropriate units. I = Part B Submit Request Answer μА I= Value Submit How much current is the dead battery alone able to drive through the starter motor? Express your answer with the appropriate units. μA Value Units Request Answer ? Units ?

A 12 V car battery dies not so much because its voltage drops but because chemical reactions increase its internal resistance. A good battery connected with jumper cables can both start the engine and recharge the dead battery. Consider the automotive circuit of (Figure 1). Figure 0.01 ΩΣ + 12 V 050 ΩΣ Jumpers Good battery 8V Dead battery 1 of 1 > 0.05 ΩΣ Starter motor ▼ Part A How much current could the good battery alone drive through the starter motor? Express your answer with the appropriate units. I = Part B Submit Request Answer μА I= Value Submit How much current is the dead battery alone able to drive through the starter motor? Express your answer with the appropriate units. μA Value Units Request Answer ? Units ?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Educational Content: Automotive Electrical Circuits**

**Overview:**
A 12 V car battery does not fail solely due to a voltage drop; instead, chemical reactions increase its internal resistance. A good battery, when connected with jumper cables, can start an engine and recharge a dead battery. Consider the automotive circuit shown in Figure 1.

**Part A:**
- *Question:* How much current could the good battery alone drive through the starter motor?
- *Instruction:* Express your answer with the appropriate units.

**Input Field:**
- Current, \( I = \) [Enter Value] [Select Units]

- [Submit] [Request Answer]

**Part B:**
- *Question:* How much current is the dead battery alone able to drive through the starter motor?
- *Instruction:* Express your answer with the appropriate units.

**Input Field:**
- Current, \( I = \) [Enter Value] [Select Units]

- [Submit] [Request Answer]

**Diagram Explanation (Figure 1):**
The diagram illustrates an electrical circuit with the following components:
- **Good Battery:** Voltage of 12 V, followed by a small internal resistance of 0.01 Ω.
- **Jumper Cables:** Represented as part of the circuit.
- **Dead Battery:** Voltage of 8 V, with an internal resistance of 0.05 Ω.
- **Starter Motor:** Has an internal resistance of 0.05 Ω.

This setup allows for the analysis of the current flow through the starter motor when different batteries are in use.

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