A 12 V car battery dies not so much because its voltage drops but because chemical reactions increase its internal resistance. A good battery connected with jumper cables can both start the engine and recharge the dead battery. Consider the automotive circuit of (Figure 1). Figure 0,01 Ω 12 V 0.50 Ω Jumpers Good battery + 8 V Dead battery 0.05 1 of 1 Starter motor Submit ▾ Part C With the jumper cables attached, how much current passes through the starter motor? Express your answer with the appropriate units. Request Answer Part D HA Submit Request Answer I = Value Value Units With the jumper cables attached, how much current passes through the dead battery? Express your answer with the appropriate units. HÅ Submit Request Answer DMC Units ? ?

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A 12 V car battery dies not so much because its voltage
drops but because chemical reactions increase its
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cables can both start the engine and recharge the dead
battery. Consider the automotive circuit of (Figure 1).
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Transcribed Image Text:ome es ome ents tings ! 1 openvellum.ecollege.com/course.html?courseld=17487819&OpenVellum HMAC=2eff1f5e5c39f8fae8797554f56600c3#10001 F1 Q A X + N 2 F2 W S Item 5 A 12 V car battery dies not so much because its voltage drops but because chemical reactions increase its internal resistance. A good battery connected with jumper cables can both start the engine and recharge the dead battery. Consider the automotive circuit of (Figure 1). Figure 0.01 Ω # 3 + 12 VE Good battery 80 F3 E 0.50 Ω Jumpers D X C I $ 4 + 8 VE Dead battery 000 000 F4 R F 0.05 2: % ол оо 5 V 1 of 1 Starter motor F5 T G 6 B F6 Submit Y Part C With the jumper cables attached, how much current passes through the starter motor? Express your answer with the appropriate units. I = Submit Part D MacBook Air Value Submit Request Answer H & 7 With the jumper cables attached, how much current passes through the dead battery? Express your answer with the appropriate units. I = Value μα Request Answer N μA F7 Request Answer P Pearson 8 Units Units DII F8 M ( 9 ? K ? 8 F9 O L F10 P F11 + 11 [ ? * 5 of 5 Constants F12 } ]
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