A 1125 g sample of ground water is found to contain 0.0755 g of arsenic. Calculate the concentration of arsenic in parts per million, ppm. concentration: Ppm
A 1125 g sample of ground water is found to contain 0.0755 g of arsenic. Calculate the concentration of arsenic in parts per million, ppm. concentration: Ppm
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
A 1125 g sample of groundwater is found to contain 0.0755 g of arsenic. Calculate the concentration of arsenic in parts per million (ppm).
**Solution:**
To find the concentration in ppm, use the formula:
\[ \text{ppm} = \left( \frac{\text{mass of solute (g)}}{\text{mass of solution (g)}} \right) \times 10^6 \]
**Given:**
- Mass of arsenic (solute) = 0.0755 g
- Mass of groundwater (solution) = 1125 g
**Calculation:**
\[ \text{ppm} = \left( \frac{0.0755}{1125} \right) \times 10^6 \]
\[ \text{Concentration:} \]
\[ \boxed{\_\_\_\_\_\_\_\_\_\_\_} \text{ ppm} \]
\[ \text{Note: To solve, compute the fraction, multiply by } 10^6, \text{ and fill in the result in the box.} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd15a2d56-c982-4a4b-8f12-312dac46f35d%2F3a8f30ae-9955-4ea1-8e22-b46a57785e60%2F06q4gqb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A 1125 g sample of groundwater is found to contain 0.0755 g of arsenic. Calculate the concentration of arsenic in parts per million (ppm).
**Solution:**
To find the concentration in ppm, use the formula:
\[ \text{ppm} = \left( \frac{\text{mass of solute (g)}}{\text{mass of solution (g)}} \right) \times 10^6 \]
**Given:**
- Mass of arsenic (solute) = 0.0755 g
- Mass of groundwater (solution) = 1125 g
**Calculation:**
\[ \text{ppm} = \left( \frac{0.0755}{1125} \right) \times 10^6 \]
\[ \text{Concentration:} \]
\[ \boxed{\_\_\_\_\_\_\_\_\_\_\_} \text{ ppm} \]
\[ \text{Note: To solve, compute the fraction, multiply by } 10^6, \text{ and fill in the result in the box.} \]
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