A 110 Kg package is to be pushed down at constant speed on an inclined plane 4 meters long from the back of a truc meters above the ground. The coefficient of kinetic friction is equal to 0.45. A force (Fa) parallel to the inclined plane should be applied to hold back the box so that it is lowered at a constant speed. A. Draw the complete Free-Body Diagram B. Work done by Fa on the box C. Work done by friction on the

A 110 Kg package is to be pushed down at constant speed on an inclined plane 4 meters long from the back of a truc meters above the ground. The coefficient of kinetic friction is equal to 0.45. A force (Fa) parallel to the inclined plane should be applied to hold back the box so that it is lowered at a constant speed. A. Draw the complete Free-Body Diagram B. Work done by Fa on the box C. Work done by friction on the

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

1. Calculate the work done on the suitcase by F→. Express your answer with the appropriate units. 2. Calculate the work done on the suitcase by the gravitational force. Express your answer with the appropriate units. 3.Calculate the work done on the suitcase by the normal force. Express your answer with the appropriate units. 4. Calculate the work done on the suitcase by the friction force. Express your answer with the appropriate units. 5. Calculate the total work done on the suitcase. Express your answer with the appropriate units. 6. If the speed of the suitcase is zero at the bottom of the ramp, what is its speed after it has traveled 3.90 mm along the ramp? Express your answer with the appropriate units.
You lift a box off the ground and then hold it at a height above your waist. Which does not describe the work or energy in this process? A. You did positive work on the box. B. Gravity did negative work on the box C. The box's gravitational potential energy increased. D. The box's kinetic energy remained constant throughout the process.
A car is accelerated from velocity v1 to v2 in the time period of t . The mass of the car is m. The inclined angle of the hill is α. The distance travelled along the hill is L. The vertical distance travelled is H. Select the equation used to calculate the potential energy increase of the car ΔPE______ A. B. ΔPE=mgH C. ΔPE=mgL D.
A horizontal force of 150 N is applied to push a 40.0 kg box a distance 6.00 m on a rough horizontal surface. If the box moves quickly constant, determine: A. The work that reverses the 150 N force. B. The coefficient of kinetic friction between the box and the surface.
A body moves with increasing speed. Which of the following statements is true? A. The net work done on the body is positive, and the kinetic energy is increasing. B. The net work done on the body is positive, and the kinetic energy is decreasing. C. The net work done on the body is zero, and the kinetic energy is decreasing. D. The net work done on the body is negative, and the kinetic energy is increasing. E. The net work done on the body is negative, and the kinetic energy is decreasing.
7. A force of 180 N stretches a spring 0.050 m beyond its unstretched length. a. What is the spring constant of this spring? b. What magnitude of force is needed to stretch the spring 0.012 m beyond its unstretched length? C. How much work must be done to stretch the spring 0.012 m beyond its unstretched length? d. What magnitude of force is needed to compress the spring 0.025 m? e. How much work must be done to compress the spring 0.025 m?
an object is acted by a frictional force. the work done by this frictional force is a. negative because friction force is opposite its motion b. zero because fk = ukn and normal force is perpendicular to the motion c. zero because friction is not the cause of its motion d. could be positive, negative or zero because the direction of friction is unknown