A 1,088.129 N painter needs to climb d=5.845 m up a ladder (measured along its length from the point where the ladder contacts the ground), without the ladder slipping. The uniform density ladder is 16.861 m long and weighs 250 N. It rests with one end on the ground and the other end against a smooth andfrictionless vertical wall. The ladder rises at an angle of theta=50.037° above the horizontal floor. What is the friction force in units of N that the floor must exert on the ladder? Use g = 9.8 %3D m/s?. painter position d Ladder length theta

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Chapter1: Units, Trigonometry. And Vectors
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A 1,088.129N painter needs to climb d=5.845 m up a ladder (measured along its
length from the point where the ladder contacts the ground), without the ladder
slipping. The uniform density ladder is 16.861 m long and weighs 250 N. It rests with
one end on the ground and the other end against a smooth andfrictionless vertical
wall. The ladder rises at an angle of theta-50.037° above the horizontal floor. What is
the friction force in units of N that the floor must exert on the ladder? Use g = 9.8
m/s².
painter position d
Ladder length
theta
Transcribed Image Text:A 1,088.129N painter needs to climb d=5.845 m up a ladder (measured along its length from the point where the ladder contacts the ground), without the ladder slipping. The uniform density ladder is 16.861 m long and weighs 250 N. It rests with one end on the ground and the other end against a smooth andfrictionless vertical wall. The ladder rises at an angle of theta-50.037° above the horizontal floor. What is the friction force in units of N that the floor must exert on the ladder? Use g = 9.8 m/s². painter position d Ladder length theta
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