A 100% 7:07 PM Wed Feb 5 Unanswered •1 attempt left For reaction 2A + 3B → 2C + D, following data of concentration and rate was obtained Trial Initial [A] Initial [B] Initial Rate (M/sec) 10.015 M 0.200 M 3.67 × 10^-6 20.030 МО.200 М 7.33 х 10^-6 3 0.015 M 0.400 M 1.47 × 10^-5 What is the rate law of the reaction? Rate = k[A][B] Rate = k[A]^2 Rate = k[B]^2 Rate = k[B][A]^2 %3D Rate = k[A][B]^2 Submit ш

A 100% 7:07 PM Wed Feb 5 Unanswered •1 attempt left For reaction 2A + 3B → 2C + D, following data of concentration and rate was obtained Trial Initial [A] Initial [B] Initial Rate (M/sec) 10.015 M 0.200 M 3.67 × 10^-6 20.030 МО.200 М 7.33 х 10^-6 3 0.015 M 0.400 M 1.47 × 10^-5 What is the rate law of the reaction? Rate = k[A][B] Rate = k[A]^2 Rate = k[B]^2 Rate = k[B][A]^2 %3D Rate = k[A][B]^2 Submit ш

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A 100% 7:07 PM Wed Feb 5 Unanswered •1 attempt left For reaction 2A + 3B → 2C + D, following data of concentration and rate was obtained Trial Initial [A] Initial [B] Initial Rate (M/sec) 10.015 M 0.200 M 3.67 × 10^-6 20.030 M 0.200 M 7.33 × 10^-6 3 0.015 M 0.400 M 1.47 × 10^-5 The special rate constant k 1.2 x 10^-3 (1/M•sec) 9.2 × 10^-4 (1/M•sec) 1.6 x 10^-3 (1/M-sec) 6.1 × 10^-3 (1/M^2·sec) D 8.2 x 10^-3 (1/M^2•sec) Submit ш
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